60 ≥ 35 + 5t
<u>-35 </u><u> </u><u>-35 </u>
<u>25</u> ≥ <u>5t</u>
5 5
t≤5
his mistake was that he used ≤ for at least instead of using ≥. so at end, when I solved, I saw that Sven should spend 5 minutes or less on each scale.
Number of students in Math136 = 480
We are given that the number of students in Math136 is 20% more than the number of students in Math123. Let the number of students in Math123 be x. So we can set up the equation as:
Number of students in Math136 = 20% more than number of students in Math123
Number of students in Math136 = 20% more than x
480 = 20% more than x
480 = 20% of x + x
480 = 0.20x + x
480 = 1.20(x)
x = 480/1.20 = 400
This means, there are 400 students in Math123.
Answer:
x < -8
Step-by-step explanation:
3 - (2x - 5) < -4(x + 2)
3 - 2x + 5 < -4*x -4*2
-2x + 8 < -4x - 8
-2x + 4x < -8 -8
2x < -16
x < -16/2
x < -8
(24xy^3-16x^2y^2+32x^2y)/8xy
<span><span>(<span><span><span><span><span><span><span>24x</span><span>y^3</span></span>−<span><span>16<span>x^2</span></span><span>y^2</span></span></span>+<span><span>32<span>x^2</span></span>y</span></span>8</span></span>x</span>)</span><span>(y)</span></span><span> =<span><span><span>−<span><span>2<span>x^3</span></span><span>y^3</span></span></span>+<span><span>3<span>x^2</span></span><span>y^4</span></span></span>+<span><span>4<span>x^3</span></span><span>y^<span>2</span></span></span></span></span>
<em>Your answer would be 5, just the number in general.</em>
<em>>[I'ma be honest here and say I had a fraction earlier :P</em>