Segma infinity to k=2 (k!)^2/(2k)! X^2k+1
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Answer:
this is my answer but it's on you if you think this answer is correct or wrong
Actually it's
y =
it's a line. so 2 points is enough
choose x so that x+4 would be divisible by 3 :)
1) x = 2, then y = (2+6) / 3 = 2 - sketch point (2,2)
2) x = 5, then y = (5+4) / 3 = 3 - sketch point (5,3)
3) line goes though those points. use ruler :)
y =
it's a line. so 2 points is enough
choose x so that x+4 would be divisible by 3 :)
1) x = 2, then y = (2+6) / 3 = 2 - sketch point (2,2)
2) x = 5, then y = (5+4) / 3 = 3 - sketch point (5,3)
3) line goes though those points. use ruler :)