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Naily [24]
3 years ago
7

From the 12 players who will travel, the coach must select her starting line-up. She will select a player for each of the five p

ositions: center, power forward, small forward, shooting guard and point guard. However, there are only three of the 12 players who can play center. Otherwise, there are no restrictions. How many ways are there for her to select the starting line-up?
Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
7 0

Answer:

990

Step-by-step explanation:

The center position can be selected in 3 different ways, the other 4 players can be selected in combinations of 11 players (the center is already selected) taken 4 at a time.

By the Fundamental Principle of Counting, there are

3\displaystyle\binom{11}{4}=3*\displaystyle\frac{11!}{4!(11-4)!}=3*\displaystyle\frac{11!}{4!7!}=990

ways for her to select the starting line-up.

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Step-by-step explanation:

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Roman55 [17]

Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
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Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
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<u>Geometry</u>

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Step-by-step explanation:

<u>Step 1: Set up</u>

75 + 120 + 90 + ∠4 = 360

<u>Step 2: Solve</u>

  1. Add:                                                                                                                   285 + ∠4 = 360
  2. [Subtraction Property of Equality] Subtract 285 on both sides:                   ∠4 = 75
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3 years ago
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Step-by-step explanation:


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