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Naily [24]
3 years ago
7

From the 12 players who will travel, the coach must select her starting line-up. She will select a player for each of the five p

ositions: center, power forward, small forward, shooting guard and point guard. However, there are only three of the 12 players who can play center. Otherwise, there are no restrictions. How many ways are there for her to select the starting line-up?
Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
7 0

Answer:

990

Step-by-step explanation:

The center position can be selected in 3 different ways, the other 4 players can be selected in combinations of 11 players (the center is already selected) taken 4 at a time.

By the Fundamental Principle of Counting, there are

3\displaystyle\binom{11}{4}=3*\displaystyle\frac{11!}{4!(11-4)!}=3*\displaystyle\frac{11!}{4!7!}=990

ways for her to select the starting line-up.

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8 15 27 blank 20 find the blank number​
777dan777 [17]

Answer:

the blank number is 23

Step-by-step explanation:

8, 15, 27, x, 20

common ratio, r= T2÷ T1= T3÷ T2

= 15 ÷ 8 =27÷ 15

= 1.8 = 1.8

20 ÷ x = x ÷ 27

( cross multiply,)

x²= 540

x =√540

x = 23.24

x = 23

6 0
4 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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3 0
3 years ago
Read 2 more answers
A total of 640 tickets were sold for the school play. They were either adult tickets or student tickets. There were 60 fewer stu
gtnhenbr [62]

Answer:

350 adult tickets were sold

Step-by-step explanation:

Let x represent the number of adult tickets sold.

Since there were 60 fewer student tickets sold than adult tickets, the number of student tickets sold can be represented by x - 60

Create an equation that sets up these terms equal to 640, then solve for x:

(x) + (x - 60) = 640

2x - 60 = 640

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So, 350 adult tickets were sold

6 0
3 years ago
A system of linear equations contains two equations with negative reciprocal
aleksandrvk [35]

let's recall that perpendicular lines have negative reciprocal slopes, so say for a line with a slope of a/b

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{a}{b}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{b}{a}}\qquad \stackrel{negative~reciprocal}{-\cfrac{b}{a}}}

a perpendicular one will be -b/a.

what does that mean?  well, that the lines are perpendicular of course, they meet at a 90° angle, and two straight lines meeting at 90° can only meet once.

since a solution to a system of equations is where the graph meet, and these two meet  perpendicularly once, then that means only one solution.

4 0
3 years ago
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