Question

City A and city B each have 10 parks. The table shows the number of acres for each park in the two cities. City A 6 9 10 7 10 10 2 5 8 8 City B 5 10 8 11 7 12 6 5 4 5 Select from the drop-down menus to correctly complete each statement. The mean number of acres for each park for the two cities is . The range for the number of acres for parks for the two cities is .

Answer 1

Answer:

The mean number of acres for each park for the two cities is:

City A: 7.5

City B: 7.3

The range for the number of acres for parks for the two cities is : 8

Step-by-step explanation:

The table shows the number of acres for each park in the two cities.

City A:  6   9   10   7   10   10   2   5   8   8

City B :  5   10   8   11    7    12   6   5   4   5

City A:

Minimum acre of park=2

Maximum acre of park=10

Range=Maximum-Minimum

Range=10-2

Range=8

Now mean is calculated as:

$Mean=\dfrac{6+9+10+7+10+10+2+5+8+8}{10}\\\\\\Mean=\dfrac{75}{10}\\\\Mean=7.5$

City B:

Minimum acre of park=4

Maximum acre of park=12

Range=Maximum-Minimum

Range=12-4

Range=8

Now mean is calculated as:

$Mean=\dfrac{5+10+8+11+7+12+6+5+4+5}{10}\\\\\\Mean=\dfrac{73}{10}\\\\Mean=7.3$

Answer 2

the mean of each park in cityA: is 7.5

the mean of each park in cityB: is 7.3  

what i did to find the mean is that i added up all of the numbers of acres of parks in each city then divided by ten the reason i divided by ten is because there is ten numbers in each list of acres.

the range of the numbers of acres for the parks is 10

the way i found this out is that i first listed all of the numbers of acres of land for parks from both citys from least to greatest then subtracted the smallest(2) to the largest(12) which gave me 10 cause all your doing is takeing 2 form 12.