Answer:
64. 6138
66. 8.078125
Step-by-step explanation:
Let's take it one number at a time.
For number 64:
![6(2)^{1-1}=6](https://tex.z-dn.net/?f=6%282%29%5E%7B1-1%7D%3D6)
![6(2)^{2-1}=12](https://tex.z-dn.net/?f=6%282%29%5E%7B2-1%7D%3D12)
![6(2)^{3-1}=24](https://tex.z-dn.net/?f=6%282%29%5E%7B3-1%7D%3D24)
![6(2)^{4-1}=48](https://tex.z-dn.net/?f=6%282%29%5E%7B4-1%7D%3D48)
![6(2)^{5-1}=96](https://tex.z-dn.net/?f=6%282%29%5E%7B5-1%7D%3D96)
![6(2)^{6-1}=192](https://tex.z-dn.net/?f=6%282%29%5E%7B6-1%7D%3D192)
![6(2)^{7-1}=384](https://tex.z-dn.net/?f=6%282%29%5E%7B7-1%7D%3D384)
![6(2)^{8-1}=768](https://tex.z-dn.net/?f=6%282%29%5E%7B8-1%7D%3D768)
![6(2)^{9-1}=1536](https://tex.z-dn.net/?f=6%282%29%5E%7B9-1%7D%3D1536)
![6(2)^{10-1}=3072](https://tex.z-dn.net/?f=6%282%29%5E%7B10-1%7D%3D3072)
Sum = 6 + 12 + 24 + 48 + 96 + 192 + 384 + 768 + 1536 + 3072
Sum = 6138
For number 66:
![12(-\frac{1}{2})^{0}=12](https://tex.z-dn.net/?f=12%28-%5Cfrac%7B1%7D%7B2%7D%29%5E%7B0%7D%3D12)
![12(-\frac{1}{2})^{1}=-6](https://tex.z-dn.net/?f=12%28-%5Cfrac%7B1%7D%7B2%7D%29%5E%7B1%7D%3D-6)
![12(-\frac{1}{2})^{2}=3](https://tex.z-dn.net/?f=12%28-%5Cfrac%7B1%7D%7B2%7D%29%5E%7B2%7D%3D3)
![12(-\frac{1}{2})^{3}=-1.5](https://tex.z-dn.net/?f=12%28-%5Cfrac%7B1%7D%7B2%7D%29%5E%7B3%7D%3D-1.5)
![12(-\frac{1}{2})^{4}=0.75](https://tex.z-dn.net/?f=12%28-%5Cfrac%7B1%7D%7B2%7D%29%5E%7B4%7D%3D0.75)
![12(-\frac{1}{2})^{5}=-0.375](https://tex.z-dn.net/?f=12%28-%5Cfrac%7B1%7D%7B2%7D%29%5E%7B5%7D%3D-0.375)
![12(-\frac{1}{2})^{6}=0.1875](https://tex.z-dn.net/?f=12%28-%5Cfrac%7B1%7D%7B2%7D%29%5E%7B6%7D%3D0.1875)
![12(-\frac{1}{2})^{7}=-0.0078125](https://tex.z-dn.net/?f=12%28-%5Cfrac%7B1%7D%7B2%7D%29%5E%7B7%7D%3D-0.0078125)
![12(-\frac{1}{2})^{8}=0.046875](https://tex.z-dn.net/?f=12%28-%5Cfrac%7B1%7D%7B2%7D%29%5E%7B8%7D%3D0.046875)
![12(-\frac{1}{2})^{9}=-0.0234375](https://tex.z-dn.net/?f=12%28-%5Cfrac%7B1%7D%7B2%7D%29%5E%7B9%7D%3D-0.0234375)
Sum = 12 + -6 + 3 + -1.5 + 0.75 + -0.375 + 0.1875 + -0.0078125 + 0.046875 + -0.0234375
or to make things simpler:
Sum = 12 - 6 + 3 - 1.5 + 0.75 - 0.375 + 0.1875 - 0.0078125 + 0.046875 - 0.0234375
Sum = 8.078125
In order to write this quadratic equation in standard form, first note that standard form is ax^2+bx+c for quadratics, where c is the numerical value (constant), B is the coefficient of x, and a is the coefficient of x^2 and is the leading coefficient. Next, multiply the binomials of (x-7) and (x-1). You can do this by using FOIL, or by distributing each of the terms in a binomial to each of the other terms in the other binomial. (Please let me know if you need a walk through in this step in particular). Furthermore, you should then write y= (the simplified trinomial). Now, the quadratic is in standard form. To reiterate, just simplify the two binomials by multiplying them together and writing that they're equal to y.
the volume of cuboid is given by length*breadth*height
the volume of above cuboid is 6*12*125=864cubic in.
volume of below cuboid is 18*10*8=1440 cubic in.
totoal volume = 1440+864l=2304 cubic in.
Answer:
perimeter of a square= 4 times square root of area
![4 \sqrt{54} = 29.39](https://tex.z-dn.net/?f=4%20%5Csqrt%7B54%7D%20%20%3D%2029.39)