Sin2(x) +cos(x)=1
from the relation: (sin2(x) +cos2(x) =1 )
so , sin2(x)=1-cos2(x)
by subs. in the main eqn.
1-cos2(x) + cos(x) =1
by simplify the eqn.
cos(x) -cos2(x)=0
take cos(x) as a common factor
cos(x)* (1-cos(x))=0
then cos(x)=0 && cos(x)=1
cos(x)=0 if x= pi/2
& cos(x) = 1 if x = 0 , 2*pi
so the solution is x= {0,pi/2 , 2*pi}
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Answer:
y = x - 5
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = x - 3 ← is in slope- intercept form
with slope m = 1
• Parallel lines have equal slopes, hence
y = x + c ← is the partial equation of the parallel line.
To find c substitute (3, - 2) into the partial equation
- 2 = 3 + c ⇒ c = - 2 - 3 = - 5
y = x - 5 ← equation of parallel line
