Can somebody help with this question please ?

Area of a rectangle is 100 sq ft. The length is 10 ft longer than twice it’s width. What is the length and the width.

Dahasolnce [82]

The length of the rectange is 20ft and width of the 5ft.

Step-by-step explanation:

Let us consider a rectangle and its area is known to be 100 sq ft.

We are given the information that the length of the rectangle is 10ft longer than twice its width.

⇒Length l = 2w+10.

Where w is the width of the rectangle.

The formula for area of the rectangle A = length × width.

A= (2w+10)×w.

100 = $2w^2+10w$ .

0= $2w^2+10w-100$ .

Thus it forms an quadratic equation we have to solve for the solution.

0=(2w-10)(w+10).

2w-10=0. w+10=0.

2w=10. w=-10. (negative value cannot be choosed.)

w= $(\frac{10}{2} )$ .

w=5ft.

Thus width is is 5 ft.

Length = 2(5)+10.

=10+10.

=20ft.

Thus the length is 20ft.

6 0

2 years ago

How to solve? I basically want to know the first step..

inessss [21]

You have to get x alone and then do the rest of the steps

5 0

3 years ago

Read 2 more answers

Refrer to the attached picture on which question is written. This question will be done according to Pathagoras theorem. This qu

Dvinal [7]

i got something different

3 0

3 years ago

3. Solve the inequality –2(z + 5) + 20 > 6.

12345 [234]

$\boxed{-2\left(z+5\right)+20>6\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:z$

Solution:

Given inequality is:

$-2(z+5)+20>6$

We have to solve the given inequality

$-2\left(z+5\right)+20>6\\\\\mathrm{Subtract\:}20\mathrm{\:from\:both\:sides}\\\\-2\left(z+5\right)+20-20>6-20\\\\\mathrm{Simplify}\\\\-2\left(z+5\right)>-14$

$Multiply\ both\ sides\ by\ -1\ \left(reverse\:the\:inequality\right)$

Whenever we multiply or divide an inequality by a negative number, we must flip the inequality sign

$\left(-2\left(z+5\right)\right)\left(-1\right)$

Thus the solution to inequality is:

$-2\left(z+5\right)+20>6\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:z$

4 0

3 years ago

a photograph is printed in the center of a piece of paper measuring 7 cm by (x + 8) cm. The photo measures 5 cm by (x +6) cm . T

Nadusha1986 [10]

The paper is 7 cm by (x + 8) cm.

A photo is 5 cm by (x + 6) cm, and is printed in the middle of the paper.

The area of the border/space around the photo is 50 cm².

To find the area of the border around the photo, you find the area of the paper and subtract it by the area of the photo.

The area of the paper:

A = 7 · (x + 8)

The area of the photo:

A = 5 · (x + 6)

Your equation to find the area of the border around the photo is:

(7 · (x + 8)) - (5 · (x + 6)) = A

[area of paper - area of photo = area of border]

Since you know the area of the border, you can plug it in:

(7 · (x + 8)) - (5 · (x + 6)) = 50

Multiply the 7 into (x + 8), and multiply the 5 into (x + 6)

(7x + 56) - (5x + 30) = 50

Distribute/multiply the - to (5x + 30)

7x + 56 - 5x - 30 = 50

Combine like terms

2x + 26 = 50

Subtract 26 on both sides

2x = 24

Divide 2 on both sides

x = 12

7 0

3 years ago