All categories

2 years ago

Please help asap. Thanks.

Mathematics

1 answer:

GarryVolchara [31]2 years ago

6 0

400 each unit is forty

You might be interested in

A/5=b/7 if b#0 what is the value of a/b

ivann1987 [24]

Answer:

A = 20

b = 28

Step-by-step explanation:

a = 20/5 = 4

b = 28/7 = 4

7 0

3 years ago

NEED HELP ASAP ILL MARK BRAINLIEST IF ITS RIGHT!!!

Leto [7]

Answer:

f(1)=-11

f(n)=f(n-1)+22

Step-by-step explanation:

Base equation:

f(n)=-11+22(n-1)

f(1)=-11+22(1-1)

f(1)=-11+0

f(1)=-11

f(n)=-33+22n

f(n-1)=-11+22(n-2)

f(n-1)=-55+22n

-33+22n=-55+22n+x

22n gets canceled out

-33=-55+x

-33+55=x

x=22

f(n)=f(n-1)+22

5 0

3 years ago

Please answer this correctly

musickatia [10]

There are 4 quarts in 1 gallon.

3 x 4 = 12

12 + 2 = 14 quarts

Hope this helps!! :)

6 0

3 years ago

Complete. What is the Original Price?

Pani-rosa [81]

90 80% disocunt so what you do is divide that then let me know what you got

3 0

3 years ago

Read 2 more answers

The difference between the two roots of the equation 3x^2+10x+c=0 is 4 2/3 . Find the solutions for the equation.

andrezito [222]

Answer:

Given the equation: $3x^2+10x+c =0$

A quadratic equation is in the form: $ax^2+bx+c = 0$ where a, b ,c are the coefficient and a≠0 then the solution is given by :

$x_{1,2} = \frac{-b\pm \sqrt{b^2-4ac}}{2a}$ ......[1]

On comparing with given equation we get;

a =3 , b = 10

then, substitute these in equation [1] to solve for c;

$x_{1,2} = \frac{-10\pm \sqrt{10^2-4\cdot 3 \cdot c}}{2 \cdot 3}$

Simplify:

$x_{1,2} = \frac{-10\pm \sqrt{100- 12c}}{6}$

Also, it is given that the difference of two roots of the given equation is $4\frac{2}{3} = \frac{14}{3}$

i.e,

$x_1 -x_2 = \frac{14}{3}$

Here,

$x_1 = \frac{-10 + \sqrt{100- 12c}}{6}$ , ......[2]

$x_2= \frac{-10 - \sqrt{100- 12c}}{6}$ .....[3]

then;

$\frac{-10 + \sqrt{100- 12c}}{6} - (\frac{-10 + \sqrt{100- 12c}}{6}) = \frac{14}{3}$

simplify:

$\frac{2 \sqrt{100- 12c} }{6} = \frac{14}{3}$

$\sqrt{100- 12c} = 14$

Squaring both sides we get;

$100-12c = 196$

Subtract 100 from both sides, we get

$100-12c -100= 196-100$

Simplify:

-12c = -96

Divide both sides by -12 we get;

c = 8

Substitute the value of c in equation [2] and [3]; to solve $x_1 , x_2$

$x_1 = \frac{-10 + \sqrt{100- 12\cdot 8}}{6}$

$x_1 = \frac{-10 + \sqrt{100- 96}}{6}$ or

$x_1 = \frac{-10 + \sqrt{4}}{6}$

Simplify:

$x_1 = \frac{-4}{3}$

Now, to solve for $x_2$ ;

$x_2 = \frac{-10 - \sqrt{100- 12\cdot 8}}{6}$

$x_2 = \frac{-10 - \sqrt{100- 96}}{6}$ or

$x_2 = \frac{-10 - \sqrt{4}}{6}$

Simplify:

$x_2 = -2$

therefore, the solution for the given equation is: $-\frac{4}{3}$ and -2.

3 0

3 years ago