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3 years ago

If we transform y=x^2 by 5 units to the left and 8 units ups, what is the vertex of the resulting parabola?

Mathematics

2 answers:

sertanlavr [38]3 years ago

7 0

Answer: y = (x + 5)² + 8

<u>Step-by-step explanation:</u>

y = x²

left 5 units: y = (x + 5)²

up 8 units: y = (x + 5)² + 8

Burka [1]3 years ago

5 0

Answer:

(-5, 8)

Step-by-step explanation:

The vertex of y=x^2 is at the origin (0,0).

5 units to the left changes the vertex to (-5,0)

Then 8 units up makes it (-5, 8)

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Identify the expression equivalent to 4(x+x+y)-2x+8+4 by substituting x=1 and x=2

Shtirlitz [24]

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3 years ago

Rewrite this radicand as two factors, one of which is a perfect square.

seropon [69]

Answer:

$2 \sqrt{15}$

Step-by-step explanation:

1) rewrite 60 as it's prime factors.

$\sqrt{2 \times 2 \times 3 \times } 5$

2) group the smae prime factors into pairs.

$\sqrt{(2 \times 2)} \times 3 \times 5$

3) Rewrite each pair in exponent form.

$\sqrt{ {2}^{2} \times 3 \times 5 }$

4) use this role:

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5) Simplify.

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So, therefor, the answer is option 1.

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Is 5266 divisible by 2

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Please help ill give you BRAINLIEST. No links please

Nat2105 [25]

Answer:

m(arc FE) = 166°

Step-by-step explanation:

By theorem of intersecting chords and tangent of a circle,

Measure of the angle formed by a chord and tangent intersecting on the circle measure the half of the intercepted arc.

m(∠GFE) = $\frac{1}{2}\text{m (arc} FE)$

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