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padilas [110]
3 years ago
9

What is the mode of the following numbers? 4, 9, 6, 3, 4, 2

Mathematics
2 answers:
KengaRu [80]3 years ago
6 0

Answer:

4

Step-by-step explanation:

Mode is the number that appears most often

4 is the only number that appears more than once so it is the mode

xxMikexx [17]3 years ago
5 0
The mode is 4
You can find the mode by counting how many 4 are
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Evaluate the expression when n= 3.<br> n2+8n+6
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Answer:

36

Step-by-step explanation:

4 0
3 years ago
The function f(x) = 1/3x + 5 and g(x) = x^2 + 4x are shown graphed below. The negative solution to the equation f(x) = g(x) is c
sergij07 [2.7K]

Answer:

Step-by-step explanation:

4 0
3 years ago
X*2+1=10 then x=? Tell me the value of x
Trava [24]

Answer:

<h2>4.5</h2>

Step-by-step explanation:

x \times 2 + 1 = 10

2x +  1 = 10

Move constant to R.H.S and change its sign

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\frac{2x}{2}  =  \frac{9}{2}

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6 0
3 years ago
The perimeter of this isosceles triangle is 22 cm. If one side is 6 cm, what are the possible lengths of the other two sides? Pa
3241004551 [841]
We know that

<span>the isosceles triangle has two equal sides
</span>
<span>let's analyze two cases
</span>
first case
perimeter=22 cm
<span>let's suppose that the known side of 6 cm is one of the two equal sides
</span>perimeter=6+6+x
22=6+6+x-----> x=22-12----> x=10 cm

answer first case
<span>the possible lengths of the other two sides are
</span>6 cm 
10 cm

second case
let's suppose that the known side of 6 cm is the side that is not equal
perimeter=22 cm
perimeter=6+x+x
22=6+x+x----> 2x=22-6----> 2x=16-----> x=8 cm


answer second case
the possible lengths of the other two sides are
8 cm 
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4 0
3 years ago
Find 15 + (-72) show your work<br><br> I will give Brainly! Pls help!
Umnica [9.8K]

Answer: -57

Step-by-step explanation:

15 + ( - 72)

Distribute

15 - 72

When this happens, you subtract the smaller number by the bigger one, then put the sign that was on the bigger number on what you get.

72 - 15 = 57

Put a negative sign on 57

-57

15 + (-72) = -57

6 0
3 years ago
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