Answer:
(c) 714.96 = 21.6(w +4.7)
Step-by-step explanation:
The area of the rectangular park will be the product of its length and width. This relation is used to write an equation to find the original width of the park.
<h3>Width</h3>
Let w represent the original width of the park in meters. The new width is 4.7 meters more, so is represented by (w +4.7).
<h3>Other dimensions</h3>
The length of the park is given as 21.6 meters. The area is given as 714.96 square meters.
<h3>Area formula</h3>
The various dimensions of the park are related by the area formula:
A = LW
714.96 = 21.6(w +4.7)
Wheres the graph top be able to help?
Answer: My best answer would be independent
Step-by-step explanation: because you would be the one rolling the dice but you don't know what it would be landing on
Options
The circle at the new location has _____________ the original circle.
- the same center as
- twice the circumference of
- half the radius of
- the same area as
Answer:
the same area as
Step-by-step explanation:
When a circle is translated and reflected, the center of the circle will change; however, its area, circumference, radius and diameter remain the same.
This is so because, translation and reflection only affect the positioning of the circle not the size.
Considering the above analysis, we can conclude that option d answers the question correctly.
Answer:
The expression 
represents the number 
rewritten in a+bi form.
Step-by-step explanation:
The value of 
is ![i=\sqrt{-1}[tex] or [tex]i^{2}=-1[\tex].Now [tex]i^{4}](https://tex.z-dn.net/?f=i%3D%5Csqrt%7B-1%7D%5Btex%5D%20or%20%5Btex%5Di%5E%7B2%7D%3D-1%5B%5Ctex%5D.%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3E%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3ENow%20%5Btex%5Di%5E%7B4%7D)
in term of ![i^{2}[\tex] can be written as, [tex]i^{4}=i^{2}\times i^{2}](https://tex.z-dn.net/?f=i%5E%7B2%7D%5B%5Ctex%5D%20can%20be%20written%20as%2C%20%3C%2Fp%3E%3Cp%3E%5Btex%5Di%5E%7B4%7D%3Di%5E%7B2%7D%5Ctimes%20i%5E%7B2%7D)
Substituting the value,
Product of two negative numbers is always positive.
Now 
in term of ![i^{2}[\tex] can be written as, [tex]i^{3}=i^{2}\times i](https://tex.z-dn.net/?f=i%5E%7B2%7D%5B%5Ctex%5D%20can%20be%20written%20as%2C%20%3C%2Fp%3E%3Cp%3E%5Btex%5Di%5E%7B3%7D%3Di%5E%7B2%7D%5Ctimes%20i)
Substituting the value,
Product of one negative and one positive numbers is always negative.
Now 
can be written as follows,
Applying radical multiplication rule,
Now, 
and 
Now substituting the above values in given expression,
Simplifying,
Collecting similar terms,
Combining similar terms,
The above expression is in the form of a+bi which is the required expression.
Hence, option number 4 is correct.
