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torisob [31]
3 years ago
7

How to solve this? Don't just give me the answer help me learn this.

Mathematics
1 answer:
Sphinxa [80]3 years ago
6 0

Answer:

I'm not entirely sure but I think that what is says is that it wants you to find the value of x in (4x+28) to make it 116 degrees because it is that same angle. So what you do is you get (4x+28)=116 and you do this because they are the same angle so you use 116 and get it to solve x. Since I'm lazy, then I go to this website and type the equation in: m a t h w a y . c o m but without all of the spaces, I had to do that so it would let me answer this, but I'll do it the real way this time. (4x+28)=116  Their is a rule in math that as long as you do something to one side of the equal sign in the equation, you have to do it to the other and it will still work. So, you minus 28 from both sides so that you can get rid of it and you now have 4x=88. Now you should know this part but you divide 4 from both sides to make so x is alone. Now you have x=22 because you divided 4 from each side. So their is your answer: x=22.

Step-by-step explanation: If you have the answer key that you can check from to make sure you got it right because I know some teachers let you do that, then you should make sure that is right, but I am pretty sure it is.


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skad [1K]

Answer:

Disagree. Actual answer:

Step-by-step explanation:

The answer to the question is in the image below. If you want to subtract mixed numbers with unlike denominators, you need to check the greatest common denominator between all of them.

5 0
2 years ago
Select the two values of x that are roots of this equation.<br>x + 2x - 6 = 0​
VLD [36.1K]

For this case we must solve the following quadratic equation:

x ^ 2 + 2x-6 = 0

Where:

a = 1\\b = 2\\c = -6

The solution is given by:

x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}

Substituting:

x = \frac {-2 \pm \sqrt {2 ^ 2-4 (1) (- 6)}} {2 (1)}\\x = \frac {-2 \pm \sqrt {4 + 24}} {2}\\x = \frac {-2 \pm \sqrt {28}} {2}\\x = \frac {-2 \pm \sqrt {2 ^ 2 * 7}} {2}\\x = \frac {-2 \pm2 \sqrt {7}} {2}\\x = -1 \pm \sqrt {7}

Thus, we have two roots:

x_ {1} = - 1+ \sqrt {7}\\x_ {2} = - 1- \sqrt {7}

ANswer:

x_ {1} = - 1+ \sqrt {7}\\x_ {2} = - 1- \sqrt {7}

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3 years ago
Chantelle has signed up for hockey. Her parents set a limit of 40$ for costs for the season. It costs 25$ to sign up plus 0.75$
sweet [91]
X=(40-25)/.75

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What are the coordinates of the orthocenter of LMN ?
Sauron [17]

Answer:

a (1, 2.5)

Step-by-step explanation:

When talking about the orthocenter, you want to make sure that the point you are looking for is in the exact center.  Since coordinate N of the x value is 1, we can safely assume that your top two choices are either a and b.  B wouldn't work since it is not at the exact center which makes your answer A.

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