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2 years ago

Can someone please answer. There is one problem. There's a picture. Thank you!!

Mathematics

1 answer:

krok68 [10]2 years ago

5 0

Cos(-θ) = Cosθ By trigonometric identity.

<span>Cos(-360) = Cos360
</span>
Cos360 = 1

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VW | UX. Find UY 20 39 X 26 w

Lorico [155]

Answer:

39?

Step-by-step explanation:

Because the distance between U and Y is 39.

(I'm sorry if I was wrong)

7 0

2 years ago

the diagram shows a rectangle four of these rectangles are put to together as shown calculate the shaded area

yawa3891 [41]

Answer:

42cm squared

Step-by-step explanation:

You are taking 2 x 0.5cm of the smaller sides rectangles which is 1. Then what is left is 6x7 which is 42cm squared

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3 years ago

If sin(x) = 5/13, and x is in quadrant 1, then tan(x/2) equals what?

Rufina [12.5K]

$x$ is in quadrant I, so $0$ , which means $0$ , so $\dfrac x2$ belongs to the same quadrant.

Now,

$\tan^2\dfrac x2=\dfrac{\sin^2\frac x2}{\cos^2\frac x2}=\dfrac{\frac{1-\cos x}2}{\frac{1+\cos x}2}=\dfrac{1-\cos x}{1+\cos x}$

Since $\sin x=\dfrac5{13}$ , it follows that

$\cos^2x=1-\sin^2x\implies \cos x=\pm\sqrt{1-\left(\dfrac5{13}\right)^2}=\pm\dfrac{12}{13}$

Since $x$ belongs to the first quadrant, you take the positive root ( $\cos x>0$ for $x$ in quadrant I). Then

$\tan\dfrac x2=\pm\sqrt{\dfrac{1-\frac{12}{13}}{1+\frac{12}{13}}}$

$\tan x$ is also positive for $x$ in quadrant I, so you take the positive root again. You're left with

$\tan\dfrac x2=\dfrac15$

4 0

3 years ago

The lengths of sides of a right triangle are 16 meters, 30 meters, and 34 meters. The triangle is dilated by a scale factor of 4

konstantin123 [22]

Answer:

Step-by-step explanation:

to be honest you guy should just use photo math its faster and i you dont need to pay to get answer

4 0

2 years ago

Does anyone know the answer to this.

gayaneshka [121]

Answer:

PLZ MARK AS BRAINLIEST

Step-by-step explanation:

FIRST STEP:

4*3 =12

6.5*3 =19.5

SECOND STEP:

21*12*19.5 =4914

4 0

3 years ago

Read 2 more answers