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3 years ago

Can someone please help and please show work

Mathematics

1 answer:

pychu [463]3 years ago

8 0

Answer:

Step-by-step explanation:

4 and a half

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Find the value of x.

asambeis [7]

Answer: 3

Step-by-step explanation:

4x+23=7x+14

4x-7x=14-23

-3x=9

x=9/3

x=3

7 0

2 years ago

What is the solution to 4(x-1)-2(3x+5)=-3x-1

Margarita [4]

To solve this problem, we need to get the variable x alone on one side of the equation. To begin, we are going to use the distributive property twice on the left side of the equation to expand the multiplication and get rid of the parentheses.

4(x-1) - 2(3x + 5) = -3x -1

4x - 4 -6x - 10 = -3x - 1

Next, we should combine like terms on the left side of the equation. This means we should add/subtract the variable terms and the constant terms in order to simplify this equation further.

-2x - 14 = -3x - 1

Then, we have to add 3x to both sides of the equation to get the variable terms all on the left side of the equation.

x - 14 = -1

After that, we should add 14 to both sides of the equation to get the variable x alone one the left side of the equation.

x = 13

Therefore, the answer is 13.

Hope this helps!

4 0

2 years ago

Read 2 more answers

Henry sells apples. The graph shows the relationship

Eddi Din [679]

Answer:

Henry does not make money if he does not sell any apples.

Step-by-step explanation:

Henry sells apples. The graph of the relationship between the price of apples and their total weight passes through the point (0,0) or origin.

Now, we have to clarify the meaning of the point (0,0) on the graph.

We choose from the options that Henry does not make money if he does not sell any apples.

Therefore, option D will be the correct one. (Answer)

8 0

2 years ago

Given the following trigonometric ratio, enumerate the meaning ratio

Likurg_2 [28]

Answer:

The trigonometric ratios are presented below:

$\sin \theta = \frac{AC}{\sqrt{AC^{2} + BC^{2}}}$

$\cos \theta = \frac{BC}{\sqrt{AC^{2} + BC^{2}}}$

$\cot \theta = \frac{BC}{AC}$

$\sec \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{BC}$

$\csc \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{AC}$

Step-by-step explanation:

From Trigonometry we know the following definitions for each trigonometric ratio:

Sine

$\sin \theta = \frac{y}{h}$ (1)

Cosine

$\cos \theta = \frac{x}{h}$ (2)

Tangent

$\tan \theta = \frac{\sin \theta}{\cos \theta} = \frac{y}{x}$ (3)

Cotangent

$\cot \theta = \frac{\cos \theta}{\sin \theta} = \frac{x}{y}$ (4)

Secant

$\sec \theta = \frac{1}{\cos \theta} = \frac{h}{x}$ (5)

Cosecant

$\csc \theta = \frac{1}{\sin \theta} = \frac{h}{y}$ (6)

Where:

$x$ - Adjacent leg.

$y$ - Opposite leg.

$h$ - Hypotenuse.

The length of the hypotenuse is determined by the Pythagorean Theorem:

$h = \sqrt{x^{2}+y^{2}}$

If $y = AC$ and $x = BC$ , then the trigonometric ratios are presented below:

$\sin \theta = \frac{AC}{\sqrt{AC^{2} + BC^{2}}}$

$\cos \theta = \frac{BC}{\sqrt{AC^{2} + BC^{2}}}$

$\cot \theta = \frac{BC}{AC}$

$\sec \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{BC}$

$\csc \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{AC}$

6 0

2 years ago

Which one is correct

Yakvenalex [24]

Answer:

2ft

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers