1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
guajiro [1.7K]
3 years ago
5

Which of the following phrases characterizes alternation of generation in algae?

Biology
2 answers:
Natalija [7]3 years ago
8 0

Answer

The correct answer would be "Diploid sporophytic generation alternating with haploid gametophytic generation"

Alternation of generation refers to the type of life cycle often observed in lower plants. In this life cycle, plants alternate between diploid and haploid stage.

For example, a diploid sporophyte produces haploid spores through meiosis

The spores mature into haploid gametophyte which produces haploid gametes through mitosis.

The gametes fertilize and restore the ploidy by producing a diploid zygote which matures into a diploid sporophyte.

grin007 [14]3 years ago
6 0
Diploid sporophytic generation alternating with haploid gametophytic generation <span>phrases characterizes alternation of generation in algae.</span>
You might be interested in
The increase in blood flow to exercising active skeletal muscle relative to other organs is largely caused by the
defon

Answer:

muscle contraction increases interstitial fluid pressure and compresses the blood vessels within the active muscle. As a consequence, blood flow is highest when muscles relax between successive muscle contractions.

Explanation:

7 0
2 years ago
2. In Squidward's family, a blue body color (B) is dominant to green (b). Determine the phenotype for each
sveta [45]
BB and Bb would be blue because they are both dominant and bb would be green because it is recessive
8 0
3 years ago
Cystic fibrosis (CF) is one of most common recessive disorders among Caucasians it affects 1 in 1,700 newborns. What is the expe
Phantasy [73]

Answer: The expected frequency of carriers is P(Aa)=0.046.

The proportion of childs with CF is P(aa)=0.024.

25% of having a child with CF (aa).

Explanation:

Hardy-Weinberg's principle states that in a large enough population, in which mating occurs randomly and which is not subject to mutation, selection or migration, gene and genotype frequencies remain constant from one generation to the next one, once a state of equilibrium has been reached which in autosomal loci is reached after one generation. So, a population is said to be in balance when the alleles in polymorphic systems maintain their frequency in the population over generations.

Given the gene allele frequencies in the gene pool of a population, it is possible to calculate the expected frequencies of the progeny's genotypes and phenotypes. <u>If P = percentage of the allele A (dominant) and q = percentage of the allele a (recessive)</u>, the checkerboard method can be used to produce all possible random combinations of these gametes.

Note that p + q = 1, that is, the percentages of gametes A and a must equal 100% to include all gametes in the gene pool.

The genotypic frequencies added together should also equal 1 or 100%, and all the equations can be summarized as follows:

p+q=1\\(p+q)^{2}  = p^{2} +2pq+q^{2} = 1\\P(AA)=p^{2} \\P(aa)=q^{2} \\P(Aa)=2pq1

So, there are 1700 individuals and only one is affected. Since it is a recessive disorder, the genotype of that individual must be aa. So the genotypic frequency of aa is 1/1700=0.000588.

Then, P(aa)=q^{2}=0.000588. And with that we can calculate the value of q,

P(a)=q=\sqrt{0.000588}=0.024

And since we know that p+q=1, we can find out the value of p.

p+0.024=1\\1-0.024=p\\p=0.976

Next, we find out the genotypic frequency of the genotype AA:

P(A)=p=0.976\\P(AA)=p^{2} = 0.976^{2}=0.95

Now, we can find out the genotypic frequency of the genotype Aa:

P(Aa)=2pq=2 x 0.976 x 0.024 = 0.046

Notice than:

p^{2} + 2pq + q^{2} = 1\\x^{2} 0.976^{2} + 2 x 0.976 x 0.024 + 0.024^{2} = 1

Then, the expected frequency of carriers is P(Aa)=0.046

The proportion of childs with CF is P(aa)=0.024

If two parents are carriers, then their genotypes are Aa.

Gametes produced by them can only have one allele of the gene. So they can either produce A gametes, or a gametes.

In the punnett square, we can see that there genotypic ratio is 2:1:1 and the phenotypic ratio is 3:1. So, there is a probability of 25% of having an unaffected child, with both normal alleles (AA); 50% of having a carrier child (Aa) and 25% (0.25) of having a child with CF (aa).

5 0
3 years ago
As organisms grow do our cells increase in size or do they increase the numbers
Inessa05 [86]
They always increase in numbers
7 0
3 years ago
Read 2 more answers
¿Como se produce el conocimiento?
Korolek [52]

Answer:

quoi mon ami

Explanation:

Je ne connais pas ta langue car ma langue est le bisaya

6 0
3 years ago
Other questions:
  • 5. Which of the two cell reproduction processes that we learned about in this lesson is the one that is necessary for sexual rep
    15·1 answer
  • What is unique about water on Earth?
    13·2 answers
  • Describe three pieces of evidence that support the big bang theory.
    8·1 answer
  • Paraphrase four safety practices you should always use when you begin scientific inquiry
    7·1 answer
  • A living thing that does not makes its own food
    15·2 answers
  • During photosynthesis, the energy from sunlight is used to split water molecules. What happens to the hydrogen ions that are spl
    14·1 answer
  • HELP!!! Plato Biology closed out and all I had left was Final. Anyone have examples of the 50 questions so I can study
    6·1 answer
  • How does the pH of milk change when it is fermented to make yoghurt​
    13·1 answer
  • True or false<br> almost all cells have a nucleus
    15·1 answer
  • Will give brainliest <br> In the producers pool, in which molecule is the carbon found
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!