Answer:
A sample of 1068 is needed.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
The margin of error is:
95% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population proportion?
We need a sample of n.
n is found when M = 0.03.
We have no prior estimate of , so we use the worst case scenario, which is 
Then
Rounding up
A sample of 1068 is needed.
Answer:
64x^3-241x^2+296x-125
Step-by-step explanation:
Im not sure ask ur teacher
Answer:
(a) 
and 
(b) The sample variance is 
and the sample standard deviation is 
Step-by-step explanation:
(a)
The sum of these 17 sample observations is
and the sum of their squares is
(b)
The sample variance, denoted by 
, is given by
where 
Applying the above formula we get that
The sample standard deviation, denoted by <em>s</em>, is the (positive) square root of the variance:
Applying the above formula we get that
