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Roman55 [17]
3 years ago
6

A rectangular packet of drink has a width that is 2 cm less than its length.

Mathematics
1 answer:
snow_lady [41]3 years ago
6 0

Answer:

6m^2+8m-16

Step-by-step explanation:

Given that the length of the packet is l=m cm.

Then the width being 2cm less than the length becomes w=m-2 and the height being 4 cm more than its length becomes h=m+4

The total surface area of the rectangular packet is given by:

T.S.A=2(lw+lh+wh)

\implies T.S.A=2[m(m-2)+m(m+4)+(m-2)(m+4)]

We expand to get:

\implies T.S.A=2(m^2-2m+m^2+4m+m^2+4m-2m-8))

\implies T.S.A=2(3m^2+4m-8)=6m^2+8m-16

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Answer:

to find the Area of a Triangle, you have to multiply the base times the height of the triangle to find the Area.

Step-by-step explanation:

For example..

If the Base ( bottom part of the triangle) was 10 and the height ( the vertical line of the triangle) was 5, you would multiply them together to get 50. So 5o would be the area of the Triangle.

<h2><em>Hope this helps and have a Great day!</em></h2>
8 0
3 years ago
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Which number is the smallest? 5.6123 5.6245 5.6023 5.6985
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1.) Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth .x squared minus 21 x equals n
Andrew [12]
Part 1
We are given x^2-21x=-4x. This can be rewritten as x^2-18x=0.
Therefore, a=1, b=-18, c=0.
Using the quadratic formula
     x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}=\frac{-\left(-18\right)\pm \sqrt{\left(-18\right)^2-4\left(1\right)\left(0\right)}}{2\left(1\right)}
     x=\frac{18\pm 18}{2}

The values of x are
     x_1=\frac{18-18}{2}=0
     x_2=\frac{18+18}{2}=18

Part 2
Since the values of y change drastically for every equal interval of x, the function cannot be linear. Therefore, the kind of function that best suits the given pairs is a quadratic function. 

Part 3.
The first equation is y=x^2+2.
The second equation is y=3x+20.

We have 
     x^2+2=3x+20
     x^2-3x-18=0
Factoring, we have 
     \left(x-6\right)\left(x+3\right)=0
Equating both factors to zero.
     x_1-6=0\rightarrow x_1=6
     x_2+3=0\rightarrow x_2=-3

When the value of x is 6, the value of y is 
     y=3\left(6\right)+20=38

When the value of x is -3, the value of y is 
     y=3\left(-3\right)+20=11

Therefore, the solutions are (6,38) or (-3,11)
7 0
3 years ago
the ordered pairs (0,-1),(1,0),(2,3),(3,8),(4,15) represent a function what is a rule that represents this function? Please help
yarga [219]

Answer:

The function rule is

f:  x\to \:  {x}^{2}  - 1

Step-by-step explanation:

The given ordered pairs are (0,-1), (1,0),(2,3),(3,8),(4,15)

We can observe the following pattern.

f(0) =  {0}^{2}  - 1 =  - 1

f(1) =  {1}^{2}  - 1 = 0

f(2) =  {2}^{2}  - 1 = 3

f(3) =  {3}^{2}  - 1 = 8

f(4) =  {4}^{2}  - 1 = 15

When we generalize this pattern, we obtain:

f(x) =  {x}^{2}  - 1

This is the function equation.

The function rule is

f:  x\to \:  {x}^{2}  - 1

8 0
3 years ago
A plastic storage bin is shaped like a rectangular prism. The height of the bin is 9 inches. The bottom of the bin has an area o
Charra [1.4K]

Answer:

<em>1620in³</em>

Step-by-step explanation:

Volume of a rectangular prism = BH

B is the Base area

H is the height of the prism.

Given

B = 180in²

H = 9in

get the volume of the prism

Volume of the prism  = 180 * 9

Volume of the prism  = 1620in³

<em>Hence the volume of the rectangular prism is 1620in³</em>

4 0
3 years ago
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