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3 years ago

Help pls ;) Find the geometric mean of 14 and 20

Mathematics

1 answer:

valkas [14]3 years ago

6 0

Answer:

geometric mean of 14 and 20 = 17. geometric mean of 2 and 32 = 17. geometric mean of 9 and 25 = 17. geometric mean of 25 and 35 = 30.

Step-by-step explanation:

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7. Stan is serving lemonade at the school's dance out of no

Lilit [14]

Answer: 540 cups

Step-by-step explanation:

Diameter = 20

Radius = 20/2=10

Volume of a cylinder: pi(r^2)h = 3600pi

Cone = (pi(r^2)h)/3 = (20pi)/3

3600pi/(20pi/3) = 540 cups

7 0

3 years ago

Read 2 more answers

If edging cost $2.32 per 12-inch stone, and you want a double layer of edging around your flower bed that is 6 yards by 1 yard.

aksik [14]

12 inches = 1foot
1yard = 3feet
6yards = 18feet
Rerange the question:
If edging cost $2.32 per 1foot stone, and you want a double layer of edging around your flower bed that is 18feet by 3feet. How much will edging you flower bed cost?
Perimter:
2(18+3)=42
And since you want to double it; double the perimeter too.
42(2)=84

2.32(84)=194.88

7 0

3 years ago

Read 2 more answers

4. Tyson and his friends go ice skating. Tyson must pay an initial fee of $18.30 plus $4.80 per hour.

andrew-mc [135]

Answer:

$19.20

Step-by-step explanation:

if every hour they pay$4.80 and they go ice skating for 4 hours all you have to do is multiply $4.80 x 4

5 0

3 years ago

Match the parabolas represented by the equations with their vertices. y = x2 + 6x + 8 y = 2x2 + 16x + 28 y = -x2 + 5x + 14 y = -

GaryK [48]

Consider all parabolas:

$y = x^2 + 6x + 8,\\y=x^2+6x+9-9+8,\\y=(x^2+6x+9)-1,\\y=(x+3)^2-1.$

When x=-3, y=-1, then the point (-3,-1) is vertex of this first parabola.

$y = 2x^2 + 16x + 28=2(x^2+8x+14),\\y=2(x^2+8x+16-16+14),\\y=2((x^2+8x+16)-16+14),\\y=2((x+4)^2-2)=2(x+4)^2-4.$

When x=-4, y=-4, then the point (-4,-4) is vertex of this second parabola.

$y =-x^2 + 5x + 14=-(x^2-5x-14),\\y=-(x^2-5x+\dfrac{25}{4}-\dfrac{25}{4}-14),\\y=-((x^2-5x+\dfrac{25}{4})-\dfrac{25}{4}-14),\\y=-((x-\dfrac{5}{2})^2-\dfrac{81}{4})=-(x-\dfrac{5}{2})^2+\dfrac{81}{4}.$

When x=2.5, y=20.25, then the point (2.5,20.25) is vertex of this third parabola.

$y =-x^2 + 7x + 7=-(x^2-7x-7),\\y=-(x^2-7x+\dfrac{49}{4}-\dfrac{49}{4}-7),\\y=-((x^2-7x+\dfrac{49}{4})-\dfrac{49}{4}-7),\\y=-((x-\dfrac{7}{2})^2-\dfrac{77}{4})=-(x-\dfrac{7}{2})^2+\dfrac{77}{4}.$

When x=3.5, y=19.25, then the point (3.5,19.25) is vertex of this fourth parabola.

$y =2x^2 + 7x +5=2(x^2+\dfrac{7}{2}x+\dfrac{5}{2}),\\y=2(x^2+\dfrac{7}{2}x+\dfrac{49}{16}-\dfrac{49}{16}+\dfrac{5}{2}),\\y=2((x^2+\dfrac{7}{2}x+\dfrac{49}{16})-\dfrac{49}{16}+\dfrac{5}{2}),\\y=2((x+\dfrac{7}{4})^2-\dfrac{9}{16})=2(x+\dfrac{7}{4})^2-\dfrac{9}{8}.$

When x=-1.75, y=-1.125, then the point (-1.75,-1.125) is vertex of this fifth parabola.

$y =-2x^2 + 8x +5=-2(x^2-4x-\dfrac{5}{2}),\\y=-2(x^2-4x+4-4-\dfrac{5}{2}),\\y=-2((x^2-4x+4)-4-\dfrac{5}{2}),\\y=-2((x-2)^2-\dfrac{13}{2})=-2(x-2)^2+13.$

When x=2, y=13, then the point (2,13) is vertex of this sixth parabola.

3 0

3 years ago

PLZ HELP PLZ PLZ PLZ

Temka [501]

Answer:

The top option is false.

Step-by-step explanation:

Both segments have a rate of change [slope] of ⅔. It just that their ratios have unique qualities:

$\frac{2}{3} = \frac{4}{6}$

Greatest Common Factor: 2

___ ___

BC is at a 4⁄6 slope, and AB is at a ⅔ slope. Although their quantities are unique, they have the exact same value.

I am joyous to assist you anytime.

3 0

3 years ago