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r-ruslan [8.4K]
2 years ago
8

What are the first three common multiples of 8 and 12

Mathematics
1 answer:
Nata [24]2 years ago
7 0

Answer:

24, 48, 72

Step-by-step explanation:

Common Multiples of 8: 8,16,24,32,40,48,56,64,72,80….

Common Multiples of 12: 12,24,36,48,60,72,………..

Hence the First 3 Least common multiple of 8 and 12= 24, 48, 72

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In the number 514,482,441, how is the relationship between the first pair of 4s the same as the relationship between the second
yanalaym [24]
In the 1st pair of fours the 4 on the left side is 10 times greater than the 4 on the right. The same thing with the 2nd pair of fours. The 4 on the left side is 10 greater than the 4 on the right. Hope this helps!

3 0
3 years ago
Read 2 more answers
Haruka hiked several kilometers in the morning. She hiked only 6 kilometers in the afternoon, which was 25%, percent less than s
Semenov [28]

Answer:

14 km

Step-by-step explanation:

6 km in the afternoon

x km in the morning

6= x- 25%

6= 0.75x

x= 6/0.75

x= 8 km

total 6+8= 14 km

4 0
3 years ago
A poker hand consisting of 9 cards is dealt from a standard deck of 52 cards. Find the probability that the hand contains exactl
Andrew [12]

Answer: \dfrac{^{12}C_{6}\times^{40}C_3}{^{52}C_9} or  \dfrac{228}{91885} .

Step-by-step explanation:

Given : A poker hand consisting of 9 cards is dealt from a standard deck of 52 cards.

The total number of cards in a deck 52

Number of faces cards in a deck = 12

Number of cards not face cards = 40

The total number of combinations of drawing 9 cards out of 52 cards = ^{52}C_9

Now , the combination of 9 cards such that exactly 6 of them are  face cards =  ^{12}C_{6}\times^{40}C_3

Now , the probability that the hand contains exactly 6 face cards will be :-

\dfrac{^{12}C_{6}\times^{40}C_3}{^{52}C_9}

=\dfrac{\dfrac{12!}{6!6!}\times\dfrac{40!}{3!37!}}{\dfrac{52!}{9!\times43!}}\ \ [\because\ ^nC_r=\dfrac{n!}{r!(n-r)!}]\\\\=\dfrac{228}{91885}

Hence, the probability that the hand contains exactly 6 face cards. is  \dfrac{228}{91885} .

6 0
3 years ago
The edge of a cube is 4 inches. The area of a cross section perpendicular to one face is ___square inches, and its perimeter is_
diamong [38]
Try 8 and 12.......................................

3 0
3 years ago
Read 2 more answers
Both lines pass through the point (-3,-4). one has a slope of 4 and the other has a slope of -1/4
Alchen [17]
If the question is to find the slope-intercept form of both lines, here's the answer:
Both lines pass through the point (-3,-4), so we can use these coordinates in both equations. The slope-intercept form is represented by y=mx+b, with m the slope, b the intersection of the line with Y'Y for x=0, y and x the coordinates of a point.
Let's first apply all these for the first line, with a slope of 4.
y = mx + b
y=-3; x=-4; m=4. All we need to do is find b.
-3 = 4(-4) + b
-3 = -16 + b
b=13
So the equation of the first line is y= 4x + 13.

Now, we'll do the same thing but for the second line:
y=-3; x=-4; m=-1/4, and we need to find b.
-3 = (-1/4)(-4) + b
-3 = 1 + b
b= -4
So the equation of the second line is y=(-1/4)x - 4

Hope this Helps! :)
3 0
3 years ago
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