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guapka [62]
3 years ago
6

A math test is worth 100 points and has 38 problems. Each problem is worth either 5 points or 2 points. How many problems of eac

h points value are on the test
Mathematics
2 answers:
Natasha_Volkova [10]3 years ago
5 0
Let x be the number of 5 points question.
Let y be the number of 2 points question.

Total number of questions is 38
x + y = 38 

Total points is 100
5x + 2y = 100

x + y = 38 ------------- (1)
5x + 2y = 100 ---------(2)

From (1):
x + y = 38
x = 38 - y -------------- sub into (2)
5(38 - y) + 2y = 100
190 - 5y + 2y = 100
3y = 90
y = 30 ------------------ sub into (1)
x + 30 = 38
x = 38 - 30
x = 8

There are 8 5-point questions and 30 2-point questions
aleksklad [387]3 years ago
3 0

Let x be the number of 5 points question.

Let y be the number of 2 points question.


Total number of questions is 38

x + y = 38 


Total points is 100

5x + 2y = 100


x + y = 38 ------------- (1)

5x + 2y = 100 ---------(2)


From (1):

x + y = 38

x = 38 - y -------------- sub into (2)

5(38 - y) + 2y = 100

190 - 5y + 2y = 100

3y = 90

y = 30 ------------------ sub into (1)

x + 30 = 38

x = 38 - 30

x = 8


There are 8 5-point questions and 30 2-point questions

hope this helps you

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2x+5y=-3<br>3x-y=21<br>help me
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Problem:
Solve
2
x
+
5
y
=
−
3
;
3
x
−
y
=
21
Steps:
I will try to solve your system of equations.
3
x
−
y
=
21
;
2
x
+
5
y
=
−
3
Step: Solve
3
x
−
y
=
21
for y:
3
x
−
y
+
−
3
x
=
21
+
−
3
x
(Add -3x to both sides)
−
y
=
−
3
x
+
21
−
y
−
1
=
−
3
x
+
21
−
1
(Divide both sides by -1)
y
=
3
x
−
21
Step: Substitute
3
x
−
21
for
y
in
2
x
+
5
y
=
−
3
:
2
x
+
5
y
=
−
3
2
x
+
5
(
3
x
−
21
)
=
−
3
17
x
−
105
=
−
3
(Simplify both sides of the equation)
17
x
−
105
+
105
=
−
3
+
105
(Add 105 to both sides)
17
x
=
102
17
x
17
=
102
17
(Divide both sides by 17)
x
=
6
Step: Substitute
6
for
x
in
y
=
3
x
−
21
:
y
=
3
x
−
21
y
=
(
3
)
(
6
)
−
21
y
=
−
3
(Simplify both sides of the equation)
Answer:
y
=
−
3
and
x
=
6

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Answer: 1.5

Step by step explain:
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