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7nadin3 [17]
2 years ago
7

To the nearest degree what is the measure of each exterior angle of a regular dodecagon

Mathematics
1 answer:
malfutka [58]2 years ago
3 0

Answer:

30^{\circ}

Step-by-step explanation:

We are asked to find the measure of each exterior angle of a regular dodecagon.

We know that a regular dodecagon is a 12 sided regular polygon with each side equal.

We know that measure of each angle of n-sided regular polygon can be found using formula:

\text{Each exterior angle}=\frac{360^{\circ}}{n}

Upon substituting n=12 in above formula, we will get:

\text{Each exterior angle of a regular dodecagon}=\frac{360^{\circ}}{12}

\text{Each exterior angle of a regular dodecagon}=30^{\circ}

Therefore, the measure of each exterior angle of a regular dodecagon is 30 degrees.

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Which angles are supplementary to each other? Select all that apply.
Orlov [11]

Supplementary angles are angles that together, for an angle of 180°. Straight lines are also 180°, so what you need to look for in this exercise are angles, next to eachother, on the same straight line.

those are:

1,2

1,4

2,3

5,6

5,8

6,7

7,8

3,4

so the right answers are option 1 and 2

6 0
2 years ago
Read 2 more answers
Parallelogram JKLM has vertices J(-1, 6), K(0, 9), L(6, −3), and M(3, −3). What is the coordinates of the image if the parallelo
Digiron [165]

Answer: (\dfrac13,-2),\ (0,-3),\ (-2,1),\ (-1,1) .

Step-by-step explanation:

Transformation rule for dilation:

(x,y)\to(kx,ky) , where k = scale factor

Given : Scale factor = -\dfrac13

Parallelogram JKLM has vertices J(-1, 6), K(0, 9), L(6, −3), and M(3, −3)

Vertices after dilation:

(-1,6)\to(-1\times\dfrac{-1}{3},6\times\dfrac{-1}{3})=(\dfrac13,-2)

(0,9)\times(0\times-\dfrac13,9\times-\dfrac13)=(0,-3)

(6,-3)\to(6\times-\dfrac13,\ -3\times-\dfrac13)=(-2,1)

(3,-3)\to (3\times-\dfrac13,\ -3\times-\dfrac13)=(-1,1)

Hence, the coordinates of the image if the parallelogram = (\dfrac13,-2),\ (0,-3),\ (-2,1),\ (-1,1) .

8 0
2 years ago
Please help me with this question <br><br> image attached
algol [13]

Answer:

Not enough information. For this to be SAS, the single tick mark would need to be located on the line CB and ED.

Step-by-step explanation:


6 0
3 years ago
Ryan planted 125 trees on my tree farm 28% of rum or maple trees and the rest of them are pine trees. Kioshi helped plant 125 tr
VashaNatasha [74]

Answer:

Ryan planted more maple trees than Kioshi.

Step-by-step explanation:

Given:

Total number of tress planted by Ryan = 125

Percent of maples tree planted by Ryan = 28%

Total number of tress planted by Kioshi = 125

We need to find who planted more maple trees.

Solution:

First we will find the number of maple tree planted by Ryan.

So we can say that;

the number of maple tree planted by Ryan is equal to Percent of maples tree planted by Ryan multiplied by Total number of tress planted by Ryan and then divided by 100.

framing in equation form we get;

the number of maple tree planted by Ryan = \frac{28}{100}\times 125 = 35

Hence Ryan planted 35 maple trees on the tree farm.

Now we will find number of maple tree planted by Kioshi.

But Given:

or every maple trees there are four pine trees

Let the number of maple tree planted by Kioshi be 'x'.

Number of pine trees = 4x

Now we know that;

Total number of tress planted by Kioshi is equal to sum of Number of pine trees and number of maple tree.

framing in equation form we get;

x+4x=125\\\\5x=125

Dividing both side by 5 we get;

\frac{5x}{5}=\frac{125}{5}\\\\x=25

Hence Kioshi planted 25 maple trees in the park.

So we can say that.

Ryan planted more maple trees than Kioshi.

7 0
3 years ago
Help me find the answer
never [62]
The answer is letter C.
7 0
3 years ago
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