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3 years ago

The sum of two numbers is 12. The difference between the numbers is for. What are the two numbers?

Mathematics

2 answers:

den301095 [7]3 years ago

8 0

Answer:

8 and 4

Step-by-step explanation:

Let's call one number x and the other 'y' using the information above we can form and solve an equation.

The sum of two numbers is 12:

x + y = 12

The difference between the two numbers is 4

x - y = 4

What are the two numbers, well lets solve the equation and find out

x + y = 12

x - y = 4

→ We can the 'x's together which will cancel out 'y'

2x = 16

→ Divide both sides by 2 to isolate 'x' and find the value of one number

x = 8

→ Substitute x = 8 into x + y = 12 to rearrange the equation and find the value of 'y' or the other number

8 + y = 12

→ Minus both sides by 8 to isolate 'y' and find the value of the other number

y = 4

So the two numbers are 4 and 8. Also we can check using the information provided in the question

"The sum of two numbers is 12" → Does 8 + 4 = 12 → Yes

"The difference between the numbers is 4" → Does 8 - 4 = 4 → Yes

So that confirms that 8 and 4 are the solutions to this question

8_murik_8 [283]3 years ago

6 0

Answer:

The two numbers are 8 and 4

Step-by-step explanation:

x is one number

y is the other number

x+y = 12

x - y = 4

Add the two equations together

x+y = 12

x - y = 4

-----------------

2x = 16

Divide by 2

2x/2 = 16/2

x = 8

Now find y

x+y = 12

8+y = 12

y = 12-8

y = 4

The two numbers are 8 and 4

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Answer:

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Step-by-step explanation:

0,2,3,4,5,6,7,8

There are 8 options, 3 of which are greater than 5

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Step-by-step explanation:

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3 years ago

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Ganezh [65]

Answer:

$y(1+x)+x-5\ln xy=C$

Step-by-step explanation:

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$(1-\frac{5}{y}+x)\frac{dy}{dx}+y=\frac{5}{x}-1$

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Taking all variables on right sides.

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Let as assume,

$M=-\frac{5}{x}+1+y$ and $N=1-\frac{5}{y}+x$

Find partial derivatives $\frac{\partial M}{\partial y}$ and $\frac{\partial N}{\partial x}$

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7 0

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olchik [2.2K]

Answer:

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Step-by-step explanation:

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simplified its 1/3

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