Answer:
x=15
Step-by-step explanation:
divide 12/20 by 4 to get 3/5 then multiply by 3 to get your value of x
Answer:
15+10x>_75
Step-by-step explanation:
so last one
Answer:
1 m/s2
Step-by-step explanation:
Olive Oyl's weight = 10 × 9.81 = 98.1 N
This weight is a force acting downward because it is due to gravity.
Popeye pulls Olive Oyl up with a force of 108.1 N. Both forces act vertically but in opposite directions. Hence their resultant, R, is their difference and is in the direction of the larger force.
R = 108.1 N - 98.1 N = 10 N
This force causes an acceleration, a, on the mass, m, of Popeye.
R = ma
a = R/m = 10 N/10 kg = 1 m/s2
if the diameter is 20, the its radius must be half that or 10.
![\textit{area of a sector of a circle}\\\\ A=\cfrac{\theta \pi r^2}{360}~~ \begin{cases} r=radius\\ \theta =\stackrel{degrees}{angle}\\[-0.5em] \hrulefill\\ A=5\pi \\ r=10 \end{cases}\implies \begin{array}{llll} 5\pi =\cfrac{\theta \pi (10)^2}{360}\implies 5\pi =\cfrac{5\pi \theta }{18} \\\\\\ \cfrac{5\pi }{5\pi }=\cfrac{\theta }{18}\implies 1=\cfrac{\theta }{18}\implies 18=\theta \end{array}](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20sector%20of%20a%20circle%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7B%5Ctheta%20%5Cpi%20r%5E2%7D%7B360%7D~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%20%5Ctheta%20%3D%5Cstackrel%7Bdegrees%7D%7Bangle%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20A%3D5%5Cpi%20%5C%5C%20r%3D10%20%5Cend%7Bcases%7D%5Cimplies%20%5Cbegin%7Barray%7D%7Bllll%7D%205%5Cpi%20%3D%5Ccfrac%7B%5Ctheta%20%5Cpi%20%2810%29%5E2%7D%7B360%7D%5Cimplies%205%5Cpi%20%3D%5Ccfrac%7B5%5Cpi%20%5Ctheta%20%7D%7B18%7D%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B5%5Cpi%20%7D%7B5%5Cpi%20%7D%3D%5Ccfrac%7B%5Ctheta%20%7D%7B18%7D%5Cimplies%201%3D%5Ccfrac%7B%5Ctheta%20%7D%7B18%7D%5Cimplies%2018%3D%5Ctheta%20%5Cend%7Barray%7D)
Answer:
yes
Step-by-step explanation:
Substitute x = 2 and y = 2 into both equations and if both are true then (2, 2) is a solution of the system.
y = x, that is
2 = 2 ← True
x + 2y = 6, that is
2 + 2(2) = 2 + 4 = 6 ← True
Thus (2, 2) is a solution of the system