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trapecia [35]
3 years ago
10

Suppose a triangle has two sides of length 3and 4 and that the angle between these two sides is 60. What is the length of the th

ird side of the triangle?

Mathematics
1 answer:
tangare [24]3 years ago
5 0

9514 1404 393

Answer:

  A.  √13

Step-by-step explanation:

You can make an educated guess and come to the right conclusion.

The triangle is nearly an equilateral triangle. A triangle with two sides 3 and an angle of 60° would have a third side of 3. A triangle with two sides of 4 and an angle of 60° would have a third side of 4.

So, the third side must be between 3 and 4. Here is an evaluation of the answer choices:

__

A -- between 3 and 4, the correct choice

B -- 3, too short

C -- 1.73, too short

D -- more than 4, too long

__

The question can be answered using your triangle solver app on your calculator, or using the Law of Cosines.

  c = √(a^2 +b^2 -2ab·cos(C))

  c = √(3^2 +4^2 -2·3·4·(1/2)) = √(9 +16 -12)

  c = √13 . . . . . length of the side opposite the 60° angle

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Answer:

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Step-by-step explanation:

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5 0
3 years ago
ΔRST ≅ ΔXYZ. If RS = 13, YZ = 11, and XZ = 9, what is XY? A. 13 B. 9 C. 2 D. 11
Usimov [2.4K]
The answer is option "A, 13".

As both triangles are similar.
<span>ΔRST ≅ ΔXYZ.
it means RS = XY
YZ = ST
and XZ = RT
Now given that RS = 13 which is equal to XY.
Thus XY is equal to 13.</span>
6 0
3 years ago
Read 2 more answers
How many solutions in the equation below 145=10x-8x
iren2701 [21]

Answer:

One

Step-by-step explanation:

145=2x

72.5=x that's one solution.

4 0
3 years ago
What is the solution to 4 x + 6 less-than-or-equal-to 18?
Dimas [21]
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4 0
3 years ago
The diameter of circles A,C and E are 32 cm, 24cm and 14 cm respectively
Karolina [17]

Answer:

AG = 4

AH = 21

EC = 12

CH = 5

HE = 7

Step-by-step explanation:

<u><em>The complete question is</em></u>

The diameters of circles A, C and E are 32 cm, 24 cm and 14 cm respectively.

Which of the following statements are true? Select all that apply.

•AG = 4

•GC = 10

•AH = 21

•EC = 12

•EH = 5

•CH = 5

•HE = 7

The picture of the question in the attached figure

<u><em>Verify each statement</em></u>

1) AG = 4

we know that

AG=AC-GC

AC=32\2=16\ cm ----> radius of circle A

GC=24/2=12\ cm ----> radius of circle C

substitute

AG=16-12=4\ cm

therefore

The statement is true

2) GC = 10

we know that

GC=24/2=12\ cm ----> radius of circle C

therefore

The statement is false

3) AH = 21

we know that

AH=AC+CH

we have

AC=16\ cm ----> radius of circle A

CH=CE-HE

CE=12\ cm ----> radius of circle C

HE=14/2=7\ cm ----> radius of circle E

so

CH=12-7=5\ cm

AH=16+5=21\ cm

therefore

The statement is true

4) EC = 12

we know that

EC=24/2=12\ cm ----> radius of circle C

therefore

The statement is true

5) EH = 5

we know that

EH=14/2=7\ cm ----> radius of circle E

therefore

The statement is false

6) CH = 5

we know that

CH=CE-HE

CE=12\ cm ----> radius of circle C

HE=14/2=7\ cm ----> radius of circle E

so

CH=12-7=5\ cm

therefore

The statement is true

7) HE = 7

we know that

HE=14/2=7\ cm ----> radius of circle E

therefore

The statement is true

3 0
3 years ago
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