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7nadin3 [17]
3 years ago
6

Hi i’m having a hard time with this can somebody please help

Mathematics
2 answers:
KiRa [710]3 years ago
6 0

Answer:

12

Step-by-step explanation:

If you put the 24 in the place of the place of the x, the answer is 12.

I could be wrong, but I'm pretty sure that's how you do it.

Contact [7]3 years ago
6 0

Answer:

C. 12

Step-by-step explanation:

The input in an expression are the factors that are multiplied, added, divided, etc. together to get an answer (output).

In x/2, the input is 24, and it will replace x.

so 24/2 = 12.

Pls mark brainliest if this helped.

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Write an equation of the line that passes through the point (8, 1) with slope 5.
Lapatulllka [165]

Answer:

<h2>y = 5x - 39</h2>

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y=mx+b

<em>m</em><em> - slope</em>

<em>b</em><em> - y-intercept</em>

<em />

Put the value of slope <em>m = 5</em> and the coordinates of the given point (8, 1) to the equation of a line:

1=(5)(8)+b

1=40+b            <em>subtract 40 from both sides</em>

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Finally:

y=5x-39

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The sum of two numbers are 26 and their difference is 8 what is the larger number
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Which situation can be modeled by a linear function?
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For the functions f left parenthesis x right parenthesis equals 6 minus x squared and g left parenthesis x right parenthesis equ
Ksju [112]

Answer:

Step-by-step explanation:

Given the functions

F(x) = 6-x²

G(x) = x²+4x-12

A) we are to find F(x)+g(x)

F(x)+G(x) = 6-x²+x²+4x-12

F(x)+G(x) = 6+0+4x-12

F(x)+G(x) = 4x+6-12

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The domain of the function is the values of x for which the expression exists. The expression exists on all real interval i.e xER

F(x)-g(x) = 6-x²-(x²+4x-12)

F(x)-g(x) = 6-x²-x²-4x+12

F(x)-g(x) = 6-2x²+4x+12

F(x)-g(x) = -2x²+4x+6

The domain of the function is the values of x for which the expression exists. The expression exists on all real interval i.e xER

3) F(x)/G(x)

= 6-x²/x²+4x-12

The domain of the function is the values of x for which the expression exists. The expression exists on all real interval i.e xER

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