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3 years ago

What number should be added to both sides of the equation to complete the square?

Mathematics

1 answer:

Rus_ich [418]3 years ago

7 0

Answer:

add 9 to each side

Step-by-step explanation:

x^2 -6x = 5

Take the coefficient of the x term

-6

Divide by 2

-6/2=3

Square it

3^2 =9

Add 9 to each side

x^2 -6x+9 = 5+9

(x-3)^2=14

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A person standing at the edge of a cliff throws a rock upward from a height of 180ft above ground level with an initial velocity

taurus [48]

Answer: 8.73 ft/s

Step-by-step explanation:

We have the following equation that models the motion of the rock:

$h(t)=-16t^{2}+64t+180$

Where $h(t)$ is the height of the rock at a time $t$ .

Now, if $h(t)=48 ft$ we can find $t$ and then the velocity of the rock at that height:

$48=-16t^{2}+64t+180$

Rearranging the equation:

$-16t^{2}+64t+132=0$

Multiplying the equation by -1:

$16t^{2}-64t-132=0$

Solving with the quadratic formula $t=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}$ , where $a=16$ , $b=-64$ , $c=-132$ .

$t=\frac{-(-64)\pm\sqrt{(-64)^{2}-4(16)(-132)}}{2(16)}$

Choosing the positive result of the equation:

$t=5.5 s$

Since velocity $V$ is defined as the traveled distance $h(t)$ in a given time $t$ , we have:

$V=\frac{h(t)}{t}$

$V=\frac{48 ft}{5.5 s}$

$V=8.727 ft/s \approx 8.73 ft/s$ This is the velocity of the rock at the height of 48 feet

7 0

3 years ago

Please help me! Reward will be brainliest!

puteri [66]

Answer:

(9, 12)

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Question 2: What is the volume of this prism?

laiz [17]

Answer:

42 cubic units

Step-by-step explanation:

2x3x7

6 0

3 years ago

The graph of the continuous function g, the derivative of the function f, is shown above. The function g is piecewise linear for

4vir4ik [10]

A) $g=f'$ is continuous, so $f$ is also continuous. This means if we were to integrate $g$ , the same constant of integration would apply across its entire domain. Over $0$ , we have $g(x)=2x$ . This means that

$f_{0$

For $f$ to be continuous, we need the limit as $x\to1^-$ to match $f(1)=3$ . This means we must have

$\displaystyle\lim_{x\to1}x^2+C=1+C=3\implies C=2$

Now, over $x$ , we have $g(x)=-3$ , so $f_{x$ , which means $f(-5)=17$ .

b) Integrating over [1, 3] is easy; it's just the area of a 2x2 square. So,

$\displaystyle\int_1^6g(x)=4+\int_3^62(x-4)^2\,\mathrm dx=4+6=10$

c) $f$ is increasing when $f'=g>0$ , and concave upward when $f''=g'>0$ , i.e. when $g$ is also increasing.

We have $g>0$ over the intervals $0$ and $x>4$ . We can additionally see that $g'>0$ only on $0$ and $x>4$ .

d) Inflection points occur when $f''=g'=0$ , and at such a point, to either side the sign of the second derivative $f''=g'$ changes. We see this happening at $x=4$ , for which $g'=0$ , and to the left of $x=4$ we have $g$ decreasing, then increasing along the other side.

We also have $g'=0$ along the interval $-1$ , but even if we were to allow an entire interval as a "site of inflection", we can see that $g'>0$ to either side, so concavity would not change.

5 0

3 years ago

A sequence is constructed according to the following rule: its first term is 7, and each next term is one more than the sum of t

Iteru [2.4K]

Answer:

Step-by-step explanation:

According to the described rule, we have

$a_1=7\\ \\a_1^2=7^2=49\Rightarrow a_2=4+9+1=14\\ \\a_2^2=14^2=196\Rightarrow a_3=1+9+6+1=17\\ \\a_3^2=17^2=289\Rightarrow a_4=2+8+9+1=20\\ \\a_4^2=20^2=400\Rightarrow a_5=4+0+0+1=5\\ \\a_5^2=5^2=25\Rightarrow a_6=2+5+1=8\\ \\a_6^2=8^2=64\Rightarrow a_7=6+4+1=11\\ \\a_7^2=11^2=121\Rightarrow a_8=1+2+1+1=5\\ \\\text{and so on...}$

We can see the pattern

$a_5=a_8=a_{11}=a_{14}=...=5\\ \\a_6=a_9=a_{12}=a_{15}=...=8\\ \\a_7=a_{10}=a_{13}=a_{16}=...=11$

In other words, for all $k\ge 2$

$a_{3k-1}=5\\ \\a_{3k}=8\\ \\a_{3k+1}=11$

Now,

$a_{2018}=a_{3\cdot 673-1}=5$

7 0

4 years ago