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3 years ago

What is the value of x?

Mathematics

2 answers:

romanna [79]3 years ago

5 0

Answer:

Step-by-step explanation:

Find all the angles of the triangle.

A straight line is 180° therefore you do 180°-105°=75°

All the angles in the triangle added together is 180°.

Now you write it into an equation,

55+75+x=180

x=180-130

x=50°

STatiana [176]3 years ago

4 0

50

Step by step explanation

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3x – y = -1 x – 2y = -12

Leviafan [203]

The solution to the system of equation is (2, 7)

<h3>System of equation</h3>

Given the system of equation expressed as:

3x – y = -1 * 2

x – 2y = -12 * 1

________________

6x – 2y = -2

x – 2y = -12

Subtract to have;

6x-x = -2-(-12)

5x = 10

x = 2

Substitute x = 2 into 2 to have:

2 - 2y = -12

-2y = -14

y = 7

Hence the solution to the system of equation is (2, 7)

Learn more on system of equation here: brainly.com/question/25976025

#SPJ1

8 0

1 year ago

Solve for x <br> Need help asap

vlabodo [156]

Answer:

$x=55$

Step-by-step explanation:

Corresponding angles of two parallel lines are always equal. The angle on "top" of $2x+6$ corresponds with the angle marked as $x+9$ . Therefore, its measure must also be $x+9$ .

Since these two angles form one side of a line which has 180 degrees, we have the following equation:

$2x+6+x+9=180$

Combine like terms:

$3x+15=180$

Subtract 15 from both sides:

$3x=165$

Divide both sides by 3:

$x=\frac{165}{3}=\boxed{55}$

3 0

3 years ago

In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= root 2 cm.

Nata [24]

Given CD is an altitude such that AD=BC , AB=3 cm and CD= √2 cm.

Let AD=x, Since given AB=3

AD+DB=3

x+DB = 3

DB = 3-x

Since ΔBCD is rght angle triangle, let's apply Pythagoras theorem

$BC^{2} = DB^{2} +CD^{2}$

$BC^{2} = (3-x)^{2} +(\sqrt{2} )^{2}$

$BC^{2} =(3-x)^{2} +2$

Since given AD=BC,let us plugin BC=x in above step.

$x^{2} =(3-x)^{2} +2$

$x^{2} =9-6x+x^{2} +2$

6x=11

x= $\frac{11}{6}$

Now we know AD=x= $\frac{11}{6}$ and given CD=√2.

Let us apply Pythagoras theorem for ΔACD

$AC^{2} =AD^{2} +DC^{2}$

$AC^{2} = (\frac{11}{6} )^{2} +(\sqrt{2} )^{2}$

$AC^{2} =\frac{193}{36}$

$AC=\sqrt{\frac{193}{36} }$ = 2.315cm

3 0

3 years ago

This is uhh due by 8 tommorow mornin please help me

Ira Lisetskai [31]

1 Simplify

x to

≤

−

+5≤−4

2 Subtract

5 from both sides.

≤

−

≤−4−5

3 Simplify

−

−4−5 to

−

−9.

≤

−

≤−9

4 Multiply both sides by

≤

−

x≤−9×3

5 Simplify

9×3 to

27.

≤

−

x≤−27

I hope this help you

6 0

3 years ago

This is for a mastery

valkas [14]

Answer:b

Step-by-step explanation:

3 0

3 years ago