All categories

2 years ago

Find the slope. Find the slope

Mathematics

1 answer:

creativ13 [48]2 years ago

6 0

Answer:

m=-2

Step-by-step explanation:

The two given points are: (-3, -2) and (-2, -4)

The equation for slope is m= $\frac{y_2-y_1}{x_2-x_1}$

m= $\frac{(-4)-(-2)}{(-2)-(-3)}$

m=-2/1

m=-2

You might be interested in

The school that Emily goes to is selling tickets to the annual dance competition.

Vilka [71]

Answer:

price for senior citizen is $11

price for child ticket is $8

4 0

3 years ago

The y-intercept of the line whose equation is 7x - 4y = 8 is what

Anni [7]

The y intercept is when x is 0. So, we have to plug in 0 for x. You can do this in many different ways as well.
7(0)-4y=8
-4y=8
Divide both sides by -4.
Y=-2
So, the Y intercept is -2 (0,-2).

6 0

3 years ago

When a data set is normally distributed, about how much of the data fall within one standard deviation of the mean?

Bezzdna [24]

That would be 68% answer

6 0

3 years ago

SOMEONE PLEASE HELLPPPP

ipn [44]

Answer:

93.39

Step-by-step explanation:

So the sum of exterior angles of the convex octagon is: 360 degrees

This means if we add all the equations that represent each angle, we can set it equal to 360 and solve for x

$(x+14) + (2x-3) + (3x+8) + (3x+16) + (2x-17) + (3x-4) + (3x-12) + (6x)$

Group like terms

$(x+2x+3x+3x+2x+3x+3x+6x) + (14-3+8+16-17-4-12)$

Add like terms

$23x+2$

Now let's set the sum of exterior angles to 360

$23x+2 = 360$

Subtract 2 from both sides

$23x=358$

Divide both sides by 23

$x\approx 15.565$

So by looking at all these, it appears that 6x is the highest value, given that x is positive. The way I estimated, is approximately 15.5, whenever I saw an equation like x+14, I estimated it's about 2x, since 14 is not exactly, but close to 15.5. I did this with each polynomial given. You could also manually check each one

Original equation

Subsitute

6(15.565)

Simplify

$93.39$

7 0

2 years ago

A study was recently conducted at a major university to estimate the difference in the proportion of business school graduates w

sveta [45]

Answer:

$(0.1875-0.274) - 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.1412$

$(0.1875-0.274) + 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.0318$

And the 95% confidence interval would be given (-0.1412;-0.0318).

We are confident at 95% that the difference between the two proportions is between $-0.1412 \leq p_A -p_B \leq -0.0318$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p_A$ represent the real population proportion for business

$\hat p_A =\frac{75}{400}=0.1875$ represent the estimated proportion for Business

$n_A=400$ is the sample size required for Business

$p_B$ represent the real population proportion for non Business

$\hat p_B =\frac{137}{500}=0.274$ represent the estimated proportion for non Business

$n_B=500$ is the sample size required for non Business

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

And replacing into the confidence interval formula we got:

$(0.1875-0.274) - 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.1412$

$(0.1875-0.274) + 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.0318$

And the 95% confidence interval would be given (-0.1412;-0.0318).

We are confident at 95% that the difference between the two proportions is between $-0.1412 \leq p_A -p_B \leq -0.0318$

7 0

3 years ago