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nadya68 [22]
3 years ago
6

There are 20 students in a club. Next year, some new students will join.

Mathematics
1 answer:
Lunna [17]3 years ago
6 0
C=students who will join
X=students who are in the club in total

20+c=x
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If 3220 = 80+7, what is the value of c?
Setler79 [48]

Answer:

Correct option is

C

36.25

Modal class =30−40

So we have, l=30,f0=12,f1=32,f2=20 and h=10

⇒  Mode=l+2f1−f0f2f1−f0×h

                  =30+2×32−12−2032−12×10

                  =30+6.25

                  =36.25

∴  Mode =36.25

8 0
3 years ago
For flvs math 7th grade, there is and end of course segment 2 review video, and there is a phrase in it that we need to tell the
alexandr402 [8]

Answer:

whos ur math teacher

Step-by-step explanation:

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2 years ago
31.Helppoo with 31. Work and explanation of why
kow [346]
The answer is C. $47.22
3 0
3 years ago
Determine whetherfis a function from the set of all bitstrings to the set of integers if
ipn [44]

Answer:

a) Not a function

b) It is a function

c) It is a function

Step-by-step explanation:

a) f(S) is not completly well defined, becuase if the bistring has multiple zeros, you need to pick one and there is not specified method in how you would do so. Another reason for which f is not well defined as a function is that for a bistring with only 1's, f is not defined because there is no zero.

b) This is a function. f(S) returns a concrete and unique integer number for each bistring S. If the bistring has only zeros, the f(S) = 0.

c) This is well defined as a function. It compensates for the failures of the first definition:

- If multiple zeros appears in S, you pick the first one, so there is one possible value for f(S)

-If no zeros appear, f is still well defined because it takes the value 0, as specified in the definition.

8 0
3 years ago
Simplify this: log√24+ log6​
Kitty [74]

simplifying log\sqrt{24}+log6 we get log(12\sqrt{6})

Step-by-step explanation:

We need to simplify: log\sqrt{24}+log6

Solving:

Applying the rule:

log a + log b = log(ab)

log\sqrt{24}+log6\\=log(6\sqrt{24})\\\sqrt{24} = \sqrt{2*2*2*3} =\sqrt{2^2*6} =\sqrt{2^2} \sqrt{6}=2\sqrt{6}\\  Putting\,\,value:\\=log(6*2\sqrt{6})\\=log(12\sqrt{6})

So, simplifying log\sqrt{24}+log6 we get log(12\sqrt{6})

Keywords: Simplifying Logarithms

Learn more about Simplifying Logarithms at:

  • brainly.com/question/11921476
  • brainly.com/question/10633485
  • brainly.com/question/5758530

#learnwithBrainly

3 0
3 years ago
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