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Softa [21]
3 years ago
9

Solve the following problem: 1 2/4 + 2 1/16

Mathematics
1 answer:
Paha777 [63]3 years ago
6 0
First you find an equivalent fractions for both of them that have the same denominator.
8/16 + 1/16 = 9/16
If you can simplify the fraction then simplify.

Then you add the whole # s
1 + 2 =3

3 9/16
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Which is the graph of g(x) = 2x – 1 + 3?
nadya68 [22]

Answer:

Your question is not very clear, hope I get what you want

Step-by-step explanation:

2x-1+3

=2x+2

=2(x+1)

7 0
2 years ago
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NEED HELP ( due tomorrow )
mariarad [96]
What is it you need help with?
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Fritz benjamin buys a car costing $12300. He agrees to make payment at the end of each month period for 8 years. He pays 7.2% in
loris [4]
12300=X[((1-(1+(0.072/12)^(-12*8))/(0.072/12)]
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3 years ago
8 ÷ 1/3 I forgot how to do this please help me
Olegator [25]
Simplify the following:
8/(1/3)

Multiply the numerator of 8/(1/3) by the reciprocal of the denominator. 8/(1/3) = (8×3)/1:
8×3

8×3 = 24:
Answer:  24
5 0
3 years ago
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Which description does NOT guarantee that a quadrilateral is a square?
Ivahew [28]
Let's go through the choices one by one

------------------------------------------
Choice A

If all sides are congruent, then this figure is a rhombus (by definition). If all angles are congruent, then we have a rectangle. Combine the properties of a rhombus with the properties of a rectangle and we have a square.

In terms of "algebra", you can think
rhombus+rectangle = square

Or you can draw out a venn diagram. One circle represents the set of all rhombuses; another circle represents the set of all rectangles. The overlapping region is the set of all squares. The overlapping region is inside both circles at the same time.

So we can rule out choice A. This guarantees we have a square when we want something that isn't a guarantee.

------------------------------------------
Choice B

If we had a parallelogram with perpendicular diagonals, then we can prove that we have a rhombus (all four sides congruent). However, we don't know anything about the four angles of this parallelogram. Are they congruent? We don't know. So we can't prove this figure is a rectangle. The best we can say is that it's a rhombus. It may or may not be a rectangle. There isn't enough info about the rectangle & square part.

This is why choice B is the answer. We have some info, but not enough to be guaranteed everytime.

------------------------------------------
Choice C

This is a repeat of choice A. Having "all right angles" is the same as saying "all angles congruent". This is because "right angle" is the same as saying "90 degrees". So we can rule out choice C for identical reasons as we did with choice A.

------------------------------------------
Choice D

As mentioned before in choice A, if we know that a quadrilateral is a rectangle and a rhombus at the same time, then the figure is also a square. This is always true, so we are guaranteed to have a square. We can cross choice D off the list.

------------------------------------------

Once again, the final answer is choice B


3 0
3 years ago
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