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andre [41]
3 years ago
5

A square has a triangular hole in it. What is the area of the figure?

Mathematics
1 answer:
Sonja [21]3 years ago
7 0
<h3>168 in 2 and then 132 in 2</h3>
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Evaluate expression an the property used of (8-8)+21
Setler [38]
The answer is 21 because you do PEMDAS first. (8-8) is 0. And 0+21 is 21
6 0
3 years ago
Use the graph of the polynomial function to find the factored form of the
Anarel [89]

The factored form of the related polynomial is (x - 1)(x - 9)

<h3>How to determine the factored form of the related polynomial?</h3>

In this question, the given parameter is the attached graph

From the graph, we can see that the curve crosses the x-axis at two different points

These points are the zeros of the polynomial function.

From the graph, the points are

x = 1 and x = 9

Set these points to 0

x - 1 = 0 and x - 9 = 0

Multiply the above equations

(x - 1)(x - 9) = 0

Remove the equation

(x - 1)(x - 9)

Hence, the factored form of the related polynomial is (x - 1)(x - 9)

Read more about polynomial at:

brainly.com/question/4142886

#SPJ1

4 0
2 years ago
The point slope form of a line that has a slope of -2 and passes through point (5,-2) is shown below.
Likurg_2 [28]
Insert the point, (5,-2) with the slope of the line to figure out the equation. You can either use point-slope form, or plug it for for slope-intercept form.

Slope-intercept form:
-2 = -2(5) + b
-2 = -10 + b
Add 10 on both sides
8 = b

Thus,

y = -2x + 8

Answer is B
4 0
2 years ago
Which problem can be solved using the equation shown? 2 dollars and 50 cents x minus 2 dollars = 10 dollars and 50 cents
Kisachek [45]

Answer:

Look below.

Step-by-step explanation:

$2.50*-$2.00=10.50

This isn't right so I don't know what you're asking for...

5 0
3 years ago
Read 2 more answers
50 POINTSS!!!
Yuri [45]
(A) Either of
• rotation 180° about point B
• reflection across point B

(B) If the transformation is rigid, the corresponding sides and angles are congruent.

(C) The sequence of letters tells you the correspondence.
  AB ⇔ DB
  AC ⇔ DE
  BC ⇔ BE
  ∠A ⇔ ∠D
  ∠ABC ⇔ ∠DBE
  ∠C ⇔ ∠E
5 0
3 years ago
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