The coordinates of three vertices of square ABCD are A(−212,112),B(−212,−3), and C(2,112).
1 answer:
Answer:
<em>P=760</em>
Step-by-step explanation:
Three of the coordinates of the square ABCD are A(-212,112) B(-212,-3) C(2,112). The image below shows the square is not ABCD but ABDC. In fact, this is not a square, as we'll prove later.
Note the x-coordinate of A and B are the same. It means this side is parallel to the y-axis. Also, the y-coordinate of A and C are the same, meaning this side is parallel to the x-axis. The missing point D should have the same x-coordinate as C and y-coordinate as B, i.e. D=(2,-3).
This shape has sides that are parallel to both axes.
To calculate the perimeter we find the length of two sides.
The distance from A to B is the difference between their y-axis:
w=112-(-3)=115
The distance from A to C is the difference between their x-axis:
l=2-(-212)=215
It's evident this is not a square but a rectangle. The perimeter is
P=2w+2l=330+430
P=760
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Answer:
y = 2
Step-by-step explanation:
The mid segment HJ is half of the third side GK , that is
HJ = GK , substitute values
2y = (y + 6) ← multiply both sides by 2 to clear the fraction
4y = y + 6 ( subtract y from both sides )
3y = 6 ( divide both sides by 3 )
y = 2