The device is ; a modem.
Hope this helps
Answer:
Explanation:
print(list1)
['C++', 'JAVA', 'ASP.PHP']
[2:-2]
Gets 2 position(C++) to -2 position(ASP.PHP), JAVA is in the Middle
print(list2)
[]
Gets middle of C++(nothing)
print(list3)
['Python', 'JAVA', 'MySQL']
Get first, jump 3, get first...
'get', 'any', 'any', 'get', 'any', 'any', 'get', ...
Answer:
if(revenue.cents - expenses.cents < 0){
profit.dollars = revenue.dollars - expenses.dollars - 1;
profit.cents = 1 - revenue.cents - expenses.cents;
}
else{
profit.dollars = revenue.dollars - expenses.dollars;
profit.cents = revenue.cents - expenses.cents;
}
Explanation:
We know that profit is given as: revenue - expenses from the question.
From the given expression above;
if(revenue.cents - expenses.cents < 0)
then profit.dollar will be revenue.dollars - expenses.dollars - 1; the 1 is to be carry over to the cent part. And the profit.cent will be 1 - revenue.cents - expenses.cents;
else the profit.dollars and the profit.cent is computed directly without needing to carry over:
profit.dollars = revenue.dollars - expenses.dollars;
profit.cents = revenue.cents - expenses.cents;
Important printer characteristics include resolution, speed, color, and cache memory.
