Answer:
like this
Explanation:
<h3>you click answer and then<u>
<em> boom</em></u></h3>
C- A graphic designer is the awnser
A. B)
B. B) 1837 Douglass joins the East Baltimore Improvement Society
C. A) offers effects when moving from one slide to the next.
Hope this helps!!
#include<stdio.h>
#include<stdlib.h>
int comment1(FILE *fp)
{
char ch;
int count=0;
while(fscanf(fp,"%c",&ch)!=EOF)
{
if(ch=='\n')
{
return count;
}
count++;
}
return count;
}
int comment2(FILE *fp)
{
char ch;
int count=0;
while(fscanf(fp,"%c",&ch)!=EOF)
{
if(ch=='*')
{
fscanf(fp,"%c",&ch);
if(ch=='/')
{
return count;
}
count++;
}
count++;
}
return 0;
}
int main()
{
printf("Enter the file name:");
char s[1000],ch,ch1;
scanf("%s",s);
FILE*fp;
fp = fopen(s,"r");
int count=0;
while(fscanf(fp,"%c",&ch)!=EOF)
{
if(ch=='\"')
{
while(fscanf(fp,"%c",&ch)!=EOF)
{
if(ch=='\"')
{
break;
}
if(ch=='\\')
{
fscanf(fp,"%c",&ch);
}
}
}
else if(ch=='/')
{
fscanf(fp,"%c",&ch);
if(ch=='/')
{
count += comment1(fp);
}
else if(ch=='*')
{
count += comment2(fp);
}
}
}
printf("%d\n",count);
return 0;
}
It should be noted that the process of redefining the functionality of a built-in operator to operate is known as <u>operator overloading</u>.
Operator overloading simply means polymorphism. It's a manner in which the operating system allows the same operator name to be used for different operations.
Operator overloading allows the operator symbols to be bound to more than one implementation. It's vital in redefining the functionality of a built-in operator to operate on programmer-defined objects.
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brainly.com/question/25487186
