Answer:
a)aNonclassFunction (co);
Explanation:
When we call a function we just have to write the name of the variable that we are passing to the function.We don't have to write any operator.
So the function call is like this:-
function_name(var_name);
In our case it is
aNonclassFunction(co);
Hence the answer is option a.
The Chargaff's rule state that in DNA, equality often exist in quantity between the bases A and T and between the bases G and C. According to Chargaff's data, adenine must pair with thymine and guanine must pair with cytosine.
- Chargaff's gave rules for the pairing of bases. The rule is made up of base pairs in the DNA double helix.
He stated that there is a relation of A with T. The Pyrimidine Thymine (T) will always pairs with the Purine Adenine (A)
and also there is a relation of C with G and thus the Purine Guanine (G) always pair with the Pyrimidine Cytosine (C)
Erwin Chargaff was an Austrian-American biochemist. He lived from 1905-2002. It was at Columbia University that he discovered this rule.
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brainly.com/question/22955213
Answer:
True
Explanation:
As the name implies, fragmentation is simply to divide datasets into smaller fragments. When a data is too large to the extent that it has maxed the supported size of a communication container such as disk, packet, frame, or segment, the dataset is divided into various fragments in order for the communication container to access or read the information, and then it reassembles the dataset back on the receiving end.
Answer:
The program to this question can be given as:
Program:
#include<iostream> //header file
using namespace std;
int main() //main method
{
int x[10],i,largest = 0,second_largest=0,n; //variable
cout << "Enter Number of elements :"; //message
cin>>n;
cout << "Insert array elements :"; //message
for(i=0;i<n;i++) //insert elements in array
{
cin >>x[i];
}
//Finding Largest element
for(i=0;i<n;i++)
{
if (x[i]>largest)
{
largest = x[i];
}
}
//finding second largset element
for(i=0;i<n;i++)
{
if (x[i]>second_largest)
{
if(x[i]==largest)
{
continue; //Ignoring largest in order to get second largest
}
second_largest=x[i];
}
}
//print value
cout <<"Largest Number:"<<largest<<endl;
cout <<"Second Largest Number:"<<second_largest;
return 0;
}
Output:
Enter Number of elements :5
Insert array elements :33
45
75
87
23
Largest Number:87
Second Largest Number:75
Explanation:
In the above program firstly we define the header file then we define the main method in the main method we define the array and other variables. We first input the number for the size of the array. Then we insert array elements after inserting array elements we search the largest number and the second largest number in the array. To search the largest number in the array we use the loop. To search the first largest number we define a condition that array is greater than the largest number and store the value into the largest variable. Then we check the second largest number in the array for this we use two conditions that are array is greater than the second largest number in this we use another condition that is array is equal to the largest number. If the inner condition is true then it will move forward and end of an inner condition. In the outer condition, the value will be stored on the second_largest variable all the conditions will be done inner the loop. At the last we print values.
The answer is The Office Clipboard.
In most Microsoft Windows, Office Clipboard is used as a temporary storage for some software applications such as Microsoft Office Applications. It allows you to store up to 24 items either texts or graphics. For example, when you copy a text from one location this text will be temporarily stored in the clipboard until you paste them to another location.