Answer:20-8D, if that is an option
Step-by-step explanation:
Answer: ![64\ ft^3](https://tex.z-dn.net/?f=64%5C%20ft%5E3)
Step-by-step explanation:
Given
The dimension of the box is
![\text{width w=}8\ ft\\\text{height h=}2\ ft\\\text{length l=}4\ ft](https://tex.z-dn.net/?f=%5Ctext%7Bwidth%20w%3D%7D8%5C%20ft%5C%5C%5Ctext%7Bheight%20h%3D%7D2%5C%20ft%5C%5C%5Ctext%7Blength%20l%3D%7D4%5C%20ft)
Space occupied by the box is equal to its volume i.e.
![\Rightarrow V=l\times b\times h\\\Rightarrow V=4\times 8\times 2\\\Rightarrow V=64\ ft^3](https://tex.z-dn.net/?f=%5CRightarrow%20V%3Dl%5Ctimes%20b%5Ctimes%20h%5C%5C%5CRightarrow%20V%3D4%5Ctimes%208%5Ctimes%202%5C%5C%5CRightarrow%20V%3D64%5C%20ft%5E3)
The volume of the box is
.
Answer:
9.8
Step-by-step explanation:
4.9 times 2
Tan^2θ - tan<span>θ = 0
tan</span>θ ( tan<span>θ - 1) = 0
tan</span><span>θ = 0 or 1
</span>
θ = 0,180, 360 , 45 , or 225 ( where 0 =< <span>θ <= 360)</span>
Answer:
a). Yes. Area will be less than 100 square in.
b). Area of octagon = 82 in²
Step-by-step explanation:
From the picture attached,
a). Octagon is inscribed in a square having one side = 10 inches.
Since, octagon is obtained by cutting off the four equal corners of the square,
Area of octagon will be less than the area of the square.
Area of square = (side)²
= 10²
= 100 in²
Therefore, area of octagon will be less than 100 in²
b). Since, corner cut off from the square are equal in shape and area,
Area of one corner (right angle triangle) = ![\frac{1}{2}(\text{Base})(\text{Height})](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28%5Ctext%7BBase%7D%29%28%5Ctext%7BHeight%7D%29)
=
= 4.5 in²
Area of 4 corners = 4.5 × 4 = 18 in²
Area of octagon = Area of square - Area of 4 corners removed
= 100 - 18
= 82 in²