Question

The diagram below represents the net of a triangular prism. What is the surface area of the triangular prism?

Answer 1

Answer:

(C)

Step-by-step explanation:

The diagram is divided ninto 5 parts that is rectangles ABCD, CHGD, GFEH and  triangles CIH and DGJ.

Area of rectangle ABCD= $l{\times}b$

=$12{\times}6=72cm^{2}$

Area rectangle CDHG=  $l{\times}b$

=$12{\times}8=96cm^{2}$

Area rectangle HGFE= $l{\times}b$

=$10{\times}12=120cm^{2}$

Area of triangles CIH and DIG= $2{\times}\frac{1}{2}{\times}b{\times}h$

=$6{\times}8=48cm^{2}$

Surface area of the triangular prism=Area of rectangle ABCD+Area rectangle CDHG+Area rectangle HGFE+Area of triangles CIH and DIG

=$72+96+120+48=336cm^{2}$

Hence, option C is correct.