The Neva River in St. Petersburg, Russia, is 74 km long. How long is it on a map drawn to a scale of 1:2,000,000?

Mathematics

2 answers:

mina [271]4 years ago

6 0

Answer:

3.7

Step-by-step explanation:

a_sh-v [17]4 years ago

3 0

Is there a type of formula you use for scale.

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Sophia types 75 words per minute and is just starting to write a term paper . patty already has 510 words written and types at a

iren2701 [21]

The way I would look at it is that Sophia types 15 words per minute faster than Patty so every minute Sophia is 15 minutes closer to what Patty has done. 510/15=34 so after 34 minutes Sophia will have caught up to Patty

4 0

4 years ago

What is the solution to the equation 7/8 (x-1/2)= -49/80

Whitepunk [10]

Step One
Multiply both sides by 80
7/8(x - 1/2)*80 = (-49/80) * 80

Step Two
7(x - 1/2 ) * 10 = - 49 Divide both sides by 7
(x - 1/2) * 10 = -49/7
(x - 1/2) * 10 = - 7 Remove the brackets on the left.
10x - (1/2)*10 = -7
10x - 5 = - 7 Add 5 to both sides.
10x = -7 + 5
10x = -2 Divide by 10
x = -2/10
x = - 0.2

Step Three
Check
We better check this one.
7/8*(-0.2 - 1/2)
7/8* (-.2 - 0.5)
7/8* (-0.7)
- 4.9/8 Now you can do one of two things. The easiest and simplest is to multiply top and bottom by 10

-4.9*10 / 8 * 10
-49 / 80 Which is the same as the right hand side.

8 0

3 years ago

Match Term Definition

Levart [38]

The correct matches are as follows:

Line Segment
E) part of a line that has two endpoints

Plane
D) a flat surface that extends infinitely and has no thickness

Perpendicular Lines
B) two lines that intersect at 90° angles

Line
A) a series of points that extend in two directions without end

Parallel Lines
C) lines that lie in the same plane and do not intersect

Hope this answers the question. Have a nice day.

4 0

3 years ago

Read 2 more answers

Pls Help - Calc. HW dy/dx problem

GREYUIT [131]

Answer:

$\displaystyle y' = \frac{-2}{x \ln (10)[\log (x) - 2]^2}$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Addition/Subtraction]: $\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]$

Derivative Rule [Basic Power Rule]:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]: $\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

Identify.

$\displaystyle y = \frac{\log (x)}{\log (x) - 2}$

Step 2: Differentiate

[Function] Derivative Rule [Quotient Rule]: $\displaystyle y' = \frac{[\log (x) - 2][\log (x)]' - [\log (x) - 2]'[\log (x)]}{[\log (x) - 2]^2}$
Rewrite [Derivative Rule - Addition/Subtraction]: $\displaystyle y' = \frac{[\log (x) - 2][\log (x)]' - [\log (x)' - 2'][\log (x)]}{[\log (x) - 2]^2}$
Logarithmic Differentiation: $\displaystyle y' = \frac{[\log (x) - 2]\frac{1}{\ln (10)x} - [\frac{1}{\ln (10)x} - 2'][\log (x)]}{[\log (x) - 2]^2}$
Derivative Rule [Basic Power Rule]: $\displaystyle y' = \frac{[\log (x) - 2]\frac{1}{\ln (10)x} - \frac{1}{\ln (10)x}[\log (x)]}{[\log (x) - 2]^2}$
Simplify: $\displaystyle y' = \frac{\frac{\log (x) - 2}{\ln (10)x} - \frac{\log (x)}{\ln (10)x}}{[\log (x) - 2]^2}$
Simplify: $\displaystyle y' = \frac{\frac{-2}{\ln (10)x}}{[\log (x) - 2]^2}$
Rewrite: $\displaystyle y' = \frac{-2}{x \ln (10)[\log (x) - 2]^2}$