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qwelly [4]
3 years ago
15

Help me on questions 8 through 12

Mathematics
1 answer:
mr_godi [17]3 years ago
6 0
8. To find the answer you can eather multipy it for each of the sides or you can add it 6 times once for each side
15\frac{1}{4} \times 6 \\ \\ 15 \frac{1}{4} + 15 \frac{1}{4} + 15 \frac{1}{4} + 15 \frac{1}{4} + 15 \frac{1}{4} + 15 \frac{1}{4}
9. You basicly do the same thing as the previous problem but with the new numbers and you add each number 2 times

10. For are you multiply Base × Height So all you have to do is Multiply the 2 numbers shown together
2 \frac{1}{2} \times 5
11-12 Is the same but witb the new numbers

I hope this helps!
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Answer:

  • <u><em>The cost of one rose bush is $ 9 and the cost on one bunch pf ornamental grass is $ 8.</em></u>

Explanation:

Name the variables and build a system of two equations with two unknowns.

<u>1. Variable r</u>: cost of one rose bush

<u>2. Variable g</u>: cost of one bunch of ornamental grass.

<u>3. First equation</u>:

  • Shreya spent $68 on 4 rose bushes and 4 bunches of ornamental grass.

        4r + 4g = 68

<u>4. Second equation</u>:

  • Beth spent $115 on 11 rose bushes and 2 bunches of ornaments grass.

  • 11r + 2g = 115

<u>5. System of equations</u>:

  • 4r + 4 g = 68     equation 1
  • 11r + 2g = 115     equation 2

<u>6. Solve the system</u>

a) Divide the equation 1 by 2:

  • 2r + 2g  =  34     equation 1a
  • 11r + 2g = 115     equation 2

b) Subtract equation 1a from equation 2:

  • 11r - 2r = 115 - 34
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  • r = 81 / 9
  • r = 9

c) Substitute the value of r into the equation 1a:

  • 2(9) + 2g = 34
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  • g = 17 - 9
  • g = 8

<u>7. Conclusion</u>:

The cost of one rose bush is $ 9 and the cost on one bunch pf ornamental grass is $ 8.

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The answer I got is -3/140 since you must multiply first, then subtract the fractions

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