Answer:
Let L(n) be the function that gives the amount of logs stacked after n loads.
L(n) = 12 + 8(n-1)
Step-by-step explanation:
Let L(n) be the function that gives the amount of logs stacked after n loads.
Let's call for the moment the first load as L(0)
L(0)= 12
Let r be the number of logs carried in each load, then
L(n) = 12 + nr
Since L(6) (the seventh load) equals 60, we have
60 = 12 + 6r, and r = 8.
So a function for the number of loads starting from n=0 would be
L(n) = 12 + 8n
If we want to start with n=1, we simply change the variable
L(n) = 12 + 8(n-1) (n=1,2,3,...).
So L(1) = 12, L(2) = 20, L(3) = 28,...L(7) = 60 and so on.
