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creativ13 [48]
3 years ago
6

A rectangle measures 15 cm by 4 cm what's it's area

Mathematics
1 answer:
schepotkina [342]3 years ago
5 0
The way you find area is multiplying width times height, so you have to multiply 15 by 4 which equals 60. Therefore the answer is 60
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The ratio of the length to the width of a rectangular field is 3 to 2. If the field is 120 yards long, how wide is the field?
Juli2301 [7.4K]
80 yards....simple calculation...as (2/3)*120= 80
8 0
3 years ago
Which of the following is equivalent to -32^3/5?
Gala2k [10]

Answer:

-8

Step-by-step explanation:

use rule for powers (xᵃ)ᵇ = xᵃᵇ

rewrite -32 in terms of (-2)⁵ so

(-32)³/⁵ = ((-2)⁵)³/⁵ =(-2) ³ = -8

7 0
3 years ago
Evaluate the summation of 3 n plus 2, from n equals 1 to 14..
Ulleksa [173]
Summation of 3n + 2 from n = 1 to n = 14 = (3(1) + 2) + (3(2) + 2) + (3(3) + 2) + . . . + (3(14) + 2) = 5 + 8 + 11 + ... + 44 ia an arithmetic progression with first term (a) = 5, common difference (d) = 3 and last term (l) = 44 and n = 14
Sn = n/2(a + l) = 14/2(5 + 44) = 7(49) = 343

Therefore, the required summation is 343.
8 0
3 years ago
Read 2 more answers
Math 3, Urgent Help, 100 points
kakasveta [241]

It is B. Also could I please get brainliest

8 0
3 years ago
If np>5 and nq>5, estimate P (at least 10) with n=13 and p=0.5 by using the normal distribution as approximation for the b
xenn [34]

Using the normal distribution, the probability is given as follows:

P(X \geq 10) = 0.0485.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
  • The binomial distribution is the probability of x successes on n trials, with p probability of a success on each trial. It can be approximated to the normal distribution with \mu = np, \sigma = \sqrt{np(1-p)}.

The parameters for the binomial distribution are:

p = 0.5, n = 13.

Hence the mean and the standard deviation are:

  • \mu = np = 13 \times 0.5 = 6.5.
  • \sigma = \sqrt{np(1-p)} = \sqrt{13 \times 0.5 \times 0.5} = 1.8028

Using continuity correction, the desired probability is P(X > 9.5), which is <u>one subtracted by the p-value of Z when X = 9.5</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{9.5 - 6.5}{1.8028}

Z = 1.66

Z = 1.66 has a p-value of 0.9515.

1 - 0.9515 = 0.0485, then:

P(X \geq 10) = 0.0485.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

4 0
2 years ago
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