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4 years ago

Jamie has a square mirror with side lengths of 6 inches.

Mathematics

2 answers:

Sophie [7]4 years ago

8 0

Are we supposed to find the area? If so, It's 36 because 6 times 6 equals 36 :p Hope I helped.

Sidana [21]4 years ago

8 0

Area is just L•W
Since all the sides are the same just multiply 6•6.
If you are looking for perimeter just add all 4 side lengths up: L+L+W+W
6+6+6+6.

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What is the solution to the inequality? 17 < 9 + x

dezoksy [38]

Answer:

x > 8

Step-by-step explanation:

Given

17 < 9 + x ( subtract 9 from both sides )

8 < x , hence

x > 8

7 0

3 years ago

Write (3p^3)^2 without exponents

rodikova [14]

Answer:

3p*3p*3p*3p*3p*3p

Step-by-step explanation:

Multiply exponents

3p^6

expand

3p*3p*3p*3p*3p*3p = 3p^6

4 0

3 years ago

One number is 1 more than 7 times the other number. If their sum is 73 more than

kvv77 [185]

<h3>Answer:</h3>

$\boxed{\boxed{\pink{\bf The \ two \ numbers \ are \ 12 \& \ 85 . }}}$

<h3>Step-by-step explanation:</h3>

Given that , One number is 1 more than 7 times the other number. If their sum is 73 more than

twice the smaller number. And we need to find the numbers. So let us take the

First Number be x .
Second number be 7x+1 .

$\underline{\red{\boldsymbol{ According \ to \ the \ Question :- }}}$

$\bf\implies 2( Small \ no.) + 73 = Bigger \ no. + Smaller \ no.\\\\\bf\implies 2x + 73 = x + 7x + 1\\\\\bf\implies 2x + 73 = 8x + 1 \\\\\bf\implies 8x - 2x = 73-1 \\\\\bf\implies 6x = 72 \\\\\bf\implies x =\dfrac{72}{6} \\\\\bf\implies \boxed{\red{\bf x = 12 }}$

Hence the smaller number is 12 and the bigger number will be :-

$\bf \implies Number_{bigger} = 7x + 1 \\\\\bf\implies Number_{bigger} =7(12)+1\\\\\bf\implies Number_{bigger} = 84 + 1 \\\\\bf\implies \boxed{\red{\bf Number_{bigger}=85 }}$

<h3>Hence the bigger number is 85 and the smaller number is 12. </h3>

5 0

3 years ago

Read 2 more answers

Graph the functions f(x)=−6x+14 and g(x)=−2x+6 on the same coordinate plane. What are the solutions of the equation −6x+14=−2x+6

asambeis [7]

Answer:

2 AND 4

Step-by-step explanation:

Brainliest please

8 0

3 years ago

I need to find two consecutive positive integers such that the square of the first is decreased by 17 equals to 4 times the seco

aleksandrvk [35]

So, is two integers, and they must be consecutive, meaning, the next one will have to be either 1 before the first or one after... anyhow.

let's say the first integer is "a".

then a consecutive integer to that one will be just 1 hop away, or say "a + 1", so there, those are the two integers.

now, we know that

$\bf \stackrel{\textit{square of the first is decreased by 17}}{a^2-17}~~=~~\stackrel{\textit{4 times the second}}{4(a+1)}
\\\\\\
a^2-17=4a+4\implies a^2-4a-21=0\implies (a-7)(a+3)=0
\\\\\\
a=
\begin{cases}
\boxed{7}\\
-3
\end{cases}$

so, is a positive integer, so it can't be -3.

what's the second integer? well is a + 1.

5 0

3 years ago