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3 years ago

During spring tide, the sun, earth, and moon are in a straight line. This causes ...............

Physics

1 answer:

enyata [817]3 years ago

4 0

Answer:

This causes higher average tidal ranges. The gravitational pull of the Sun and moon on Earth combined cause high tides that will be higher and low tides that will be lower than average.

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A particle moves according to a law of motions=f(t),t≥0 Wheretismeasured in seconds andsin feet.a) Find the velocity at timet.b)

Ray Of Light [21]

Answer:

a) $v(t) = \frac{9}{t^2+9} - \frac{18t^2}{(t^2+9)^2}$

b) 3s

c) t < 3s

d) 1.8ft

e) particle is speeding up when t > 5.385 s and vice versa, slowing down when t < 5.385 s

Explanation:

a)Suppose the equation for motion is:

$f(t) = \frac{9t}{t^2+9}$

Then the velocity is the derivative of the motion function

$v(t) = \frac{df(t)}{dt} = (9t(t^2+9)^{-1})^'$

From here we can apply product rule

$v(t) = (9t)^{'}(t^2+9)^{-1} + (9t)((t^2+9)^{-1})^'$

$v(t) = \frac{9}{t^2+9} - \frac{9t(2t)}{(t^2+9)^2}$

$v(t) = \frac{9}{t^2+9} - \frac{18t^2}{(t^2+9)^2}$

b) The particle is at rest when v(t) = 0:

$\frac{9}{t^2+9} - \frac{18t^2}{(t^2+9)^2} = 0$

$\frac{9}{t^2+9} = \frac{18t^2}{(t^2+9)^2}$

Multiply 2 sides by $(t^2+9)^2$ we have:

$t^2 + 9 = 2t^2$

$t^2 = 9$

$t = 3s$

$\frac{9}{t^2+9} - \frac{18t^2}{(t^2+9)^2} > 0$

$\frac{9}{t^2+9} > \frac{18t^2}{(t^2+9)^2}$

Multiply 2 sides by $(t^2+9)^2$ we have:

$t^2 + 9 > 2t^2$

$t^2 < 9$

$t < 3s$

(d) As particle is moving in positive direction when t < 3s and negative direction when t > 3s, we can calculate the distance it's moving up to 3s and then after 3s

$f(3) = \frac{9*3}{3^2+9} = \frac{27}{18} = 1.5 ft$

At 3s, particle is changing direction to negative, so its position at 6s is

$f(6) = \frac{9*6}{6^2+9} = \frac{54}{45} = 1.2 ft$

Therefore from 3s to 6s it would have moved a distance of 1.5 - 1.2 = 0.3 ft

Then the total distance it has moved in the first 6 s is 1.5 + 0.3 = 1.8 ft

e) Acceleration is the derivative of velocity function:

$a(t) = \frac{dv(t)}{dt} = (\frac{9}{t^2+9} - \frac{18t^2}{(t^2+9)^2})^'$

$a(t) = -\frac{9(2(t^2+9))(2t)}{(t^2+9)^2} - \frac{36t}{(t^2+9)^2} + \frac{18t^2(2(t^2+9))(2t)}{(t^2+9)^3}$

$a(t) = -\frac{36t}{t^2+9} - \frac{36t}{(t^2+9)^2} + \frac{72t^3}{(t^2+9)^2}$

$a(t) = -\frac{54t}{t^2+9} + \frac{72t^3 - 36t}{(t^2+9)^2}$

Particle is speeding up when a(t) > 0:

$-\frac{54t}{t^2+9} + \frac{72t^3 - 36t}{(t^2+9)^2} > 0$

$\frac{72t^3 - 36t}{(t^2+9)^2} > \frac{54t}{t^2+9}$

as $t \& (t^2 + 9)^2 \geq 0$ we can multiply/divide both sides by it:

$8t^2 - 4 > 6(t^2+9)$

$8t^2 > 6t^2 + 58$

$t^2 > 29$

$t > \sqrt(29) \approx 5.385 s$

so particle is speeding up when t > 5.385 s and vice versa, slowing down when t < 5.385 s

8 0

3 years ago

Which is not a characteristic of chemical equilibrium?

dimaraw [331]

<span>The answer would be, C. The reactions go to completion</span>

7 0

4 years ago

Read 2 more answers

The drawing shows four sheets of polarizing material, each with its transmission axis oriented differently. Light that is polari

storchak [24]

Answer:

Explanation:

At the point when light is vertically polarized is incident on the polarizer whose axes are situated at angle points $\theta _1 , \theta _2 , \theta _3$ the intensity power in the wake of going through all the polarisers is given by the Malus law, applied threefold for every one of the three axes.

$I = I_o \ cos \theta _1 \ cos \theta _2 \ cos \theta _ 3$

The heading of the direction of the polarization is equivalent to the pivoted axes of the polarizer provided that light is an electromagnetic wave, its course of polarization is therefore controlled by the electric field part.

∴

When sheet A is removed, the transmitted light goes through B, at 30°.

$I = I_o \ cos ^2 \theta _1 \ cos ^2 \theta _2 \ cos^2 \theta _3$

$I = 20 \ cos ^2 30 \ cos ^2 60 \ cos ^2 30$

$I = 2.81 \ W/m^2$

When B is removed, No light passes since the axis of A and the axis of C are perpendicular to each other.

When C is removed, the intensity is indeed zero since the axes are aligned and adjusted at 90° to one another.

$\mathbf{d) \ I - I_o cos^2 (0) cos^2 (30) \ cos^2 (60)}$

$\mathbf{d = 3.75 \ W/m^2}$

3 0

3 years ago

The difference in energy () between vibrational energy levels is determined by the nature of the bond. If a photon of light poss

forsale [732]

Answer:

the statement is true

Explanation:

The bonds in the molecules give rise to irrational energy levels, are quantized, that is, they are discrete

In order for a photon to create a transition between the given levels it has to have the same energy as these two levels, it is in this case if the photon has the energy of the bond can be promised to the electron and be absorbed.

In summary the statement is true

5 0

4 years ago

an object with a mass of 70kilograms is supported at a height 8meters above the ground. what's the potential energy of the objec

ra1l [238]

Gravitational Potential Energy = mgh (m=mass; g=gravitational force(9.8N/kg); h = height)

Ug = (70kg)(9.8N/kg)(8m) = 5488J which is C.)

3 0

4 years ago