Question

How much thermal energy is absorbed when 145 g of water at 23ºC is heated until it boils and turns into vapour?

Answer 1

Answer:

the thermal energy absorbed is 46,893 J

Explanation:

Given;

mass of the water, m = 145 g = 0.145 kg

initial temperature of the water,  t₁ = 23 ⁰C

final temperature of the water, t₂ = 100 ⁰C

specific heat capacity of water, c = 4,200 J/kg.⁰C

The thermal energy absorbed is calculated as;

H = mcΔt

H = 0.145 x 4,200 x (100 - 23)

H = 46,893J

Therefore, the thermal energy absorbed is 46,893J