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olya-2409 [2.1K]
3 years ago
15

How much thermal energy is absorbed when 145 g of water at 23ºC is heated until it boils and turns into vapour?

Physics
1 answer:
True [87]3 years ago
6 0

Answer:

the thermal energy absorbed is 46,893 J

Explanation:

Given;

mass of the water, m = 145 g = 0.145 kg

initial temperature of the water,  t₁ = 23 ⁰C

final temperature of the water, t₂ = 100 ⁰C

specific heat capacity of water, c = 4,200 J/kg.⁰C

The thermal energy absorbed is calculated as;

H = mcΔt

H = 0.145 x 4,200 x (100 - 23)

H = 46,893J

Therefore, the thermal energy absorbed is 46,893J

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