Solve for x: the quantity of x plus 4 over 3 = 2. (x+4) ------- = 12 3
1 answer:
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The picture in the attached figure
we know that
If a tangent segment and a secant segment are drawn to a <span>circle </span><span>from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment
</span>so
DC²=BC*CA-----> CA=DC²/BC
DC=25
BC=14
CA=25²/14-----> CA=44.64
CA=BC+BA----> BA=CA-BC----> BA=44.64-14----> BA=30.64
BA is the diameter
hence
<span>the length of diameter BA is 30.64----> round to the nearest tenth---> 30.6
</span>
the answer is
<span>the length of diameter BA is 30.6</span>
we know that
If a tangent segment and a secant segment are drawn to a <span>circle </span><span>from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment
</span>so
DC²=BC*CA-----> CA=DC²/BC
DC=25
BC=14
CA=25²/14-----> CA=44.64
CA=BC+BA----> BA=CA-BC----> BA=44.64-14----> BA=30.64
BA is the diameter
hence
<span>the length of diameter BA is 30.64----> round to the nearest tenth---> 30.6
</span>
the answer is
<span>the length of diameter BA is 30.6</span>
Answer:
The height of deepness of submarine is 424.1 feet
Step-by-step explanation:
Given as :
The angle at which submarine drives of the surface of water = Ф = 13°
The speed at which submarine travel = s = 760 feet per minute
Let The height of deepness of submarine = h feet
The time taken to reach that deepness = t = 5 minutes
<u>According to question</u>
The height of deepness of submarine =
i.e h × cos(90 - Ф) =
Or, h × Sin(Ф) =
Or, h × Sin(13°) = 95 feet
Or, h × 0.224 = 95 feet
∴ h =
i.e h = 424.10 feet
So, The height of deepness of submarine = h = 424.10 feet
Hence, The height of deepness of submarine is 424.1 feet Answer