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4 years ago

Is the fraction 1/3 equivalent to a terminating decimal or a decimal that does not terminate?

Mathematics

1 answer:

bezimeni [28]4 years ago

4 0

It is a decimal that does not terminate. 1/3 is equivalent to .3333333333 and so on. it never ends

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The percentage of body fat of a random sample of 36 men aged 20 to 29 found a sample mean of 14.42. Find a 95% confidence interv

Rina8888 [55]

Answer:

$14.42-1.96\frac{6.95}{\sqrt{36}}=12.150$

$14.42+ 1.96\frac{6.95}{\sqrt{36}}=16.690$

So on this case the 95% confidence interval would be given by (12.150;16.690)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=14.42$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=6.95$ represent the population standard deviation

n=36 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$

Now we have everything in order to replace into formula (1):

$14.42-1.96\frac{6.95}{\sqrt{36}}=12.150$

$14.42+ 1.96\frac{6.95}{\sqrt{36}}=16.690$

So on this case the 95% confidence interval would be given by (12.150;16.690)

5 0

4 years ago

Equal measure? Need help with the questions? Question are at the top in the pic ?

leva [86]

Answer:

1. 4; 2. 32; 3. 9; 4. 8; 5. 12; 6. 16; 7. 6; 8. 8; 9. 8; 10. 8

4 0

4 years ago

Select all quantities that are proportional to the diagonal length of a square.

horsena [70]

Answer:

B. Perimeter of a square and

C. Side length of a square

Step-by-step explanation:

if n= side length of square then

Area of square is $n^{2}$
Perimeter of a square is 4×n
diagonal length of a square is $\sqrt{2}$ × n

Thus,

Perimeter of square can be expressed as

$2\sqrt{2}$ ×diagonal length of a square

Side length of a square can be expressed as

$\frac{1}{\sqrt{2} }$ ×diagonal length of a square

but Area of square is

$\frac{1}{\sqrt{2} }$ ×n×diagonal length of a square

As a Result, Area of square is <em>also dependent of the value n</em>, wheras in other cases it is <em>a proportion of diagonal length of a square</em>

5 0

3 years ago

Help please

9966 [12]

Answer:

Step-by-step explanation:

Triangular Inequalities state that in a triangle, the sides must always be less than the sum of the other two.

You would have sides x, 2x, 3x in this case and use the inequality a+b>c.

if...

a=x, b=2x, c=3x

then...

x+2x>3x

3x>3x which is false.

Therefore you cannot make a triangle with sides proportional to 1, 2, and 3.

6 0

3 years ago

Answer this please !

kompoz [17]

Answer:

x = 90°

Step-by-step explanation:

The diagonals of the kite AC and BD are perpendicular to each other

Hence x = 90°

6 0

3 years ago