Answer:
Each boxed candies are 5.98, and Each bag of chips are 6.99 Sorry if incorrect
Answer:
4032 different tickets are possible.
Step-by-step explanation:
Given : At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the first two races. If the first race runs 9 horses and the second runs 8.
To find : How many different tickets are possible ?
Solution :
In the first race there are 9 ways to pick the winner for first and second place.
Number of ways for first place - 
Number of ways for second place - 
In the second race there are 8 ways to pick the winner for first and second place.
Number of ways for first place - 
Number of ways for second place - 
Total number of different tickets are possible is


Therefore, 4032 different tickets are possible.
1. discriminant = b^2 - 4ac = (-5)^2 - (4 x 1 x 7) = 25 - 28 = -3 [imaginary root]
2. discriminant = (-5)^2 - (4 x 1 x -4) = 25 - (-16) = 25 + 16 = 41 [real and irrational root]
3. discriminant = (8)^2 - (4 x 16 x 1) = 64 - 64 = 0 [double root]
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hope it helps
Answer: I’m not sure but I think the answer is $255
Step-by-step explanation: