Answer:
7A−(I + A)³
=7A−(1³ + A³ +3.I.A² +3.1².A)
=7A−(I+ A².A+3A² +34)
= 7A-(I+A.A+3A+34) (*: A² = A)
=7A-(I+ A² +6A)
= 7A-(I+A+64)
=7A-(1+7A)
=7A-I-7A
=-1
<h2>
Answer:</h2><h2>c = -24</h2><h2 /><h2>Hope this helps!!</h2>
Answer:
Step-by-step explanation:
3x + 10??
Answer:
3 terms
Step-by-step explanation: