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statuscvo [17]
3 years ago
11

EXPLAIN: How does the amount of a substance affect the rate at which temperature changes?

Chemistry
1 answer:
Anton [14]3 years ago
4 0
The more of a substance you have the longer the reaction will take. If you have a big pot of water and a little pot of water. The little pot will heat up quicker then the bigger pot because it does not need to fill a space up. Think of it as diffusion. When you have a 500 and 50 mL beaker, and you add a blue and red dye to them both. It will only take about a minute for the dye to almost completely mix together in the 50 mL. While the 500 mL it will take much longer for dye to mix all together then it did in the 50 mL. When it is a bigger substance it takes longer for a reaction to fully expose the substance to that reaction. If you have food, if you only have one piece of food you only need to put it in for 30 seconds to 1 minute. While if you have multiple pieces of food you will need longer time to be able to heat all of the pieces. If you have a small bowl of soup and you put it in for a minute the middle will be warm. But if you had a bigger bowl and still put it in for only a minute then the middle will be cold because you did not give it enough reaction time to heat the whole substance.
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How many grams are in 3.14 moles of PI₃?
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Answer:

\boxed {\boxed {\sf 1290 \ g \ PI_3}}

Explanation:

We want to convert from moles to grams, so we must use the molar mass.

<h3>1. Molar Mass</h3>

The molar mass is the mass of 1 mole of a substance. It is the same as the atomic masses on the Periodic Table, but the units are grams per mole (g/mol) instead of atomic mass units (amu).

We are given the compound PI₃ or phosphorus triiodide. Look up the molar masses of the individual elements.

  • Phosphorus (P): 30.973762 g/mol
  • Iodine (I): 126.9045 g/mol

Note that there is a subscript of 3 after the I in the formula. This means there are 3 moles of iodine in 1 mole of the compound PI₃. We should multiply iodine's molar mass by 3, then add phosphorus's molar mass.

  • I₃: 126.9045 * 3=380.7135 g/mol
  • PI₃: 30.973762 + 380.7135 = 411.687262 g/mol

<h3>2. Convert Moles to Grams</h3>

Use the molar mass as a ratio.

\frac {411.687262 \ g \ PI_3}{ 1 \  mol \ PI_3}

We want to convert 3.14 moles to grams, so we multiply by that value.

3.14 \ mol \ PI_3 *\frac {411.687262 \ g \ PI_3}{ 1 \  mol \ PI_3}

The units of moles of PI₃ cancel.

3.14 *\frac {411.687262 \ g \ PI_3}{ 1 }

1292.698 \ g\ PI_3

<h3>3. Round</h3>

The original measurement of moles has 3 significant figures, so our answer must have the same. For the number we calculated, that is the tens place.

  • 1292.698

The 2 in the ones place tells us to leave the 9.

1290 \ g \ PI_3

3.14 moles of phosphorous triiodide is approximately equal to <u>1290 grams of phosphorus triodide.</u>

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