What is the with of the tank in cm that is0.20 meters

200 g of solid sodium hydroxide (NaOH) are dissolved in 750 mL of water. What is the concentration of this solution?

Anastaziya [24]

Answer:

6.67 M

Explanation:

Molarity = $\frac{mol}{L}$

<em>Convert 200g NaOH to moles. Convert 750 mL to L.</em>

200 g NaOH x (1 mol/39.998 g) = 5.00025... mol NaOH

750 mL x (1 L/1000 mL) = 0.750 L

<em>Substitute values into the equation.</em>

Molarity = $\frac{5.00025}{0.750}$

Molarity = 6.667... M

Molarity = 6.67 M

8 0

3 years ago

A bottle contains 158.1 grams of lead (II) sulfate (PbSO4), used for car batteries. How many moles does it contain?

Zinaida [17]

I hope this helps :)

7 0

2 years ago

At constant pressure, density of gas is inversely proportional to its temperature. This is how hot air balloon is floating in ai

Arturiano [62]

Answer:

1.08 g/L is the density of air.

Explanation:

Pressure of the gas = P (atm)

Volume of the gas = V (L)

Moles of gas = n = $\frac{w(g)}{M(g/mol)}$

Temperature of the gas = T (K)

$PV=nRt$

$PV=\frac{w}{M}\times RT$

$PM=\frac{w}{V}RT=DRT$

where:

D = density of the gas = $\frac{Mass}{Volume}$

R = universal gas constant

w = Mass of the gas

M =Molar mass of the gas

Given = P = 1.0 atm , T = 54°C = 327.15 K

Average molar mass of the gas = 29 g/mol

Putting all the given values in above equation.

$1 atm\times 29 g/mol=D\times 0.0821 atm L/mol K\times 327.15 K$

$D=\frac{1 atm\times 29 g/mol}{0.0821 atm L/mol K\times 327.15 K}$

D = 1.08 g/L

1.08 g/L is the density of air.

3 0

3 years ago

Calculate ΔH o rxn for the following reaction, after it is properly balanced with smallest whole-number coefficients: C2H6(g) +

Ne4ueva [31]

Answer:

The enthalpy of the reaction is -2855.622 kilo Joules.

Explanation:

$2C_2H_6(g) + 7O_2(g)\rightarrow 4CO_2(g) + 6H_2O(g)$

We are given:

$\Delta H^o_f_{(C_{2}H_6(g))}= -84.667 kJ/mol$

$\Delta H^o_f_{O_2((g))}= 0 kJ/mol$

$\Delta H^o_f_{CO_2((g))}= -393.5 kJ/mol$

$\Delta H^o_f_{H_2O((g))}= -241.826 kJ/mol$

The equation used to calculate enthalpy of reaction :

$\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f(product)]-\sum [n\times \Delta H^o_f(reactant)]$

The equation for the enthalpy change of the above reaction is:

$\Delta H^o_{rxn}=(4 mol\times \Delta H^o_f_{(CO_2(g))}+6 mol\times \Delta H^o_f_{(H_2O(g)))}-(2 mol\times \Delta G^o_f_{(C_{2}H_6(g))}+7 mol\times \Delta H^o_f_{(O_2(g)))$

Putting values in above equation, we get:

$\Delta H^o_{rxn}=[4 mol\times (-393.5 kJ/mol)+6 mol\times (-241.826 kJ/mol)]-[2 mol\times (-84.667 kJ/mol)+7 mol\times 0 kJ/mol]$

$=-2855.622 kJ$

The enthalpy of the reaction is -2855.622 kilo Joules.

7 0

3 years ago

How are work and power related? (site 1)

Fynjy0 [20]

Although technically energy and work are same things, there is intuitive difference between them.

work is an activity involving a force on an object and the distance traversed by the object due to the force. It can be measured by the change in energy.

Energy is capacity of doing work.For example if a something has energy of x joule it can perform x joule work.

Power is the work done in unit time.

7 0

3 years ago