Answer:
The new volume will be 5.80 L
Explanation:
Step 1: Data given
The initial volume = 29.0 L
The initial pressure = 562 torr = 562 /760 atm = 0.739474 atm
The pressure changes to 2810 torr = 2810 /760 atm = 3.697368 atm
The temperature and number of moles will not change
Step 2: Calculate the new volume
P1*V1 = P2*V2
⇒With P1 = the initial pressure = 0.739474 atm
⇒with V1 = the initial volume = 29.0 L
⇒with P2 = the increased pressure = 3.697368 atm
⇒with V2 = The new volume = TO BE DETERMINED
0.739474 atm * 29.0 L = 3.697368 atm * V2
V2 = 5.80 L
OR
562 torr * 29.0 L = 2810 torr * V2
V2 = 5.80 L
The new volume will be 5.80 L
Trihydrate - basically 3 molecules of water. Unless you're referring to the molecule 3H2O used in measuring the total body water in the case it tritiated water.
The answer is D glad to help :)<span />
The unequal sharing of electrons gives the water molecule a slight negative charge near its oxygen atom and a slight positive charge near itshydrogen atoms. When a neutral molecule has a positive area at one end and a negative area at the other, it is a polar molecule.
To determine the pH of a solution which has 0.195 M hc2h3o2 and 0.125 M kc2h3o2, we use the ICE table and the acid dissociation constant of hc2h3o2 <span>to determine the concentration of the hydrogen ion present at equilibrium. We do as follows:
HC2H3OO = H+ + </span>C2H3OO-
KC2H3OO = K+ + C2H3OO-
Therefore, the only source of hydrogen ion would be the acid. We use the ICE table,
HC2H3OO H+ C2H3OO-
I 0.195 0 0.125
C -x +x +x
------------------------------------------------------------------
E 0.195-x x 0.125 + x
Ka = <span>1.8*10^-5 = (0.125 + x) (x) / 0.195 -x
x = 2.81x10^-5 M = [H+]
pH = - log [H+]
pH = -log 2.81x10^-5
pH = 4.55
Therefore, the pH of the resulting solution would be 4.55.</span>
